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Brut [27]
2 years ago
10

What is the vertex of the following function? f(x) = 2(x+8)^2 - 2

Mathematics
1 answer:
netineya [11]2 years ago
4 0

~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ f(x)=2(x+8)^2-2\implies f(x)=2[x-(\stackrel{h}{-8})]^2\stackrel{k}{-2}~\hfill \stackrel{vertex}{(-8~~,~~-2)}

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Solution:  

Using Substitution Method:

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x-3y=-5       (Equation 2)

get the value of x from Equation 2

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Put the value of x from Equation 3 in Equation 1

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Putting value of y in equation 3

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-4x+7y=-5   (Equation 1)

x-3y=-5       (Equation 2)

Multiply equation 2 with -4 in order to eliminate the x term

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Adding Equation 1 and 3

-4x+7y=-5    

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+    -     = -   (Change Of Sign with x and y terms)

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0x-5y = -25

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y=5  

Substituting y’s value is Equation 1

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Cancellation of negative sign on both sides

x=40/4

x=10

[x,y]=[10,5]

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