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Brut [27]
2 years ago
10

What is the vertex of the following function? f(x) = 2(x+8)^2 - 2

Mathematics
1 answer:
netineya [11]2 years ago
4 0

~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ f(x)=2(x+8)^2-2\implies f(x)=2[x-(\stackrel{h}{-8})]^2\stackrel{k}{-2}~\hfill \stackrel{vertex}{(-8~~,~~-2)}

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Proportional relationships are relationships between two variables where their ratios are equivalent.

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\begin{array}{l}{\frac{6 \text { feet }}{9 \text { feet }}=\frac{n \text { feet }}{24 \text { feet }}} \\\\ {\frac{6}{9}=\frac{n}{24}} \\\\ {\text { n }=\frac{1}{3} \times 24} \\\\ {\text { n }=8}\end{array}

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