What is the vertex of the following function? f(x) = 2(x+8)^2 - 2

1 answer:

4 0

$~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ f(x)=2(x+8)^2-2\implies f(x)=2[x-(\stackrel{h}{-8})]^2\stackrel{k}{-2}~\hfill \stackrel{vertex}{(-8~~,~~-2)}$

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