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k0ka [10]
3 years ago
12

Help I need to submit this ASAP​

Mathematics
1 answer:
lesantik [10]3 years ago
5 0

Answer:  th

Step-by-step explanation:

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Fill in the table using this function rule.<br> y = 10x-3<br> X<br> -<br> 0
dexar [7]

Answer:

Step-by-step explanation:

<em>y</em> = 10(- 1) - 3 = <em>- 13</em>

<em>y</em> = 10(0) - 3 = <em>- 3 </em>

<em>y</em> = 10(1)  - 3 =<em> 7 </em>

<em>y</em> = 10(5) - 3 = <em>47</em>

5 0
3 years ago
!!!!!!!!!!!!!!!!!!!!!
S_A_V [24]

Answer:

A

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
1 ) Tim earns $12.50 an hour cleaning houses. If he works from 8:00am to 2:00pm,
AVprozaik [17]

Answer:

$75

Step-by-step explanation:

First, we will find how many hours he worked. 8:00-12:00 is 4 hours, and 12:00-2:00 is 2 hours, so he worked a total of 6 hours.

Next, we have to multiply the hours worked by his hourly wage.

12.50*6=75

8 0
3 years ago
Read 2 more answers
Let's find2. 1+5 3First write the addition with a common denominator.Then add.12— +51-4-13Х5
emmasim [6.3K]
Answer:\frac{2}{5}+\frac{1}{3}=\frac{6}{15}+\frac{5}{15}=\frac{11}{15}Explanation:

The given addition exercise is:

\frac{2}{5}+\frac{1}{3}

The LCM of the denominator (5 and 3) = 15

Multiply 2/5 by 3/3

\frac{2}{5}=\frac{2\times3}{5\times3}=\frac{6}{15}

Multiply 1/3 by 5/5

\frac{1}{3}=\frac{1\times5}{3\times5}=\frac{5}{15}

The addition becomes

\frac{6}{15}+\frac{5}{15}=\frac{11}{15}

Therefore, we can fill in the vacant boxes as shown below:

\frac{2}{5}+\frac{1}{3}=\frac{6}{15}+\frac{5}{15}=\frac{11}{15}

4 0
1 year ago
Find the maxmium area of a rectangular plot of land which can be enclosed by rope of length 60 metres​
mario62 [17]

Answer:

225 m²

Step-by-step explanation:

If W is the width of the rectangle, and L is the length, then:

60 = 2W + 2L

A = WL

Use the first equation to solve for one of the variables:

30 = W + L

L = 30 − W

Substitute into the second equation:

A = W (30 − W)

A = 30W − W²

This is a parabola, so we can find the vertex using the formula x = -b/(2a).

W = -30 / (2 × -1)

W = 15

Or, we can use calculus:

dA/dW = 30 − 2W

0 = 30 − 2W

W = 15

Solving for L:

L = 30 − W

L = 15

So the maximum area is:

A = WL

A = (15)(15)

A = 225

3 0
3 years ago
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