Two 8-foot-long 2 × 4s are cut into sections of equal length. Board A is cut into 9 equal sections, of which 5 are used. Th

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Two 8-foot-long 2 × 4s are cut into sections of equal length. Board A is cut into 9 equal sections, of which 5 are used. Th

erefore, of the board has been used; of it remains. Board B is cut into 7 equal sections, of which 4 are used. That means of the board has been used; of it remains. Which has the longest remaining section, Board A or Board B?

Mathematics

1 answer:

alexdok [17] · Answer 1 · 2023-04-22T07:41:00+03:00

Answer:

Board A

Step-by-step explanation:

Since the boards were split into equal sections, we can think of them as fractions.

$\frac{5}{9}$ of Board A was used, meaning $\frac{4}{9}$ of Board A remains.

$\frac{4}{7}$ of Board B was used, meaning $\frac{3}{7}$ of Board B remains.

To give these fractions common denominators, we multiply the numerator and denominator by the opposite denominator.

4/9 * 7/7 = 28/63

3/7 * 9/9 = 27/63

28/63 is greater than 27/63. This means that Board A has the longest remaining section.

Two​ 8-foot-long 2​ × 4s are cut into sections of equal length. Board A is cut into 9 equal​ sections, of which 5 are used. ​ Th

Two 8-foot-long 2 × 4s are cut into sections of equal length. Board A is cut into 9 equal sections, of which 5 are used. Th