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inysia [295]
3 years ago
7

Which of the following are identities? Check all that apply. A. cot2x + 1 = csc2x B. tan2x = 1 - sec2x C. sin2x = 1 + cos2x D. s

in2x + cos2x = 1
Mathematics
1 answer:
kirill115 [55]3 years ago
4 0

I'll assume those are squares.  We know D is an identity:

\sin^2 x + \cos ^2 x = 1

Dividing through by \sin ^2 x

1 + \cot^2 x = \csc^2 x

That's A.

Dividing the original through by \cos ^2 x

\tan^2 x + 1 = \sec^2 x

Not quite B, wrong sign on tangent.  

C has the wrong sign on cosine squared as well.

Identities: A & D
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Hi there!  

»»————- ★ ————-««

I believe your answer is:  

\frac{4^2}{2^2} = 4\\\\(8-4)*4=4^2\\\\2^2 + 2^2 = 8

»»————- ★ ————-««  

Here’s why:  

\boxed{\text{Simplifying each expression:}}\\\\\frac{4^2}{2^2}\\---------\\\\\\rightarrow \frac{16}{4}\\\\\rightarrow \boxed{4}\\\\ \boxed{\frac{4^2}{2^2}=4}

⸻⸻⸻⸻

(8-4) * 4\\-----------\\\rightarrow (4)*4\\\\\rightarrow \boxed{16}\\\\\text{We can also tell...}\\\\4^2 = 4 * 4 = \boxed{16}\\\\\text{So...}\\\\\boxed{(8-4)*4 = 4^2}

⸻⸻⸻⸻

2^2 + 2^2\\--------------\\\rightarrow 4 + 2^2\\\\\rightarrow 4 + 4\\\\\rightarrow \boxed{8}

⸻⸻⸻⸻

»»————- ★ ————-««  

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