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3 years ago

There are 460 students enrolled at freedom academy. 40 percent of the students are male. How many males attend Freedom academy?

Mathematics

2 answers:

arsen [322]3 years ago

8 0

Answer:

184

Step-by-step explanation:

convert percentage into decimal:

40% = 40/100 = 0.4

Therefore 40% of 460 = 0.4 x 460 = 184

charle [14.2K]3 years ago

8 0

Solution:

Note that:

460 students = Total
40% = Male

Use the percentage formula to find out how much males attended the freedom academy.

Total males/Total students x 100 = % of males
=> x/460 x 100 = 40%
=> x/46 x 10 = 40%
=> x/23 x 5 = 40%
=> 5x/23 = 40%
=> 5x = 920
=> x = 920/5 = 184

184 males attended the Freedom academy.

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3 years ago

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ch4aika [34]

Answer:

The answer to your question is: y ≥ - x + 6 and y ≥ x - 4

Step-by-step explanation:

Look of a pairs of points for each graph

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A(0, 6) B (5, 1) C (7,3) D(5, 1)

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3 years ago

The distribution of SAT II Math scores is approximately normal with mean 660 and standard deviation 90. The probability that 100

gayaneshka [121]

Using the normal distribution and the central limit theorem, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

In this problem:

The mean is of 660, hence $\mu = 660$ .

The standard deviation is of 90, hence $\sigma = 90$ .

A sample of 100 is taken, hence $n = 100, s = \frac{90}{\sqrt{100}} = 9$ .

The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is 1 subtracted by the p-value of Z when X = 670, hence:

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$