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3 years ago

12

Lucas has a quarter of a fruit bar. Stella had half of a different fruit bar. The piece Lucas had was larger. How would Stella's

piece be smaller

2 answers:

drek231 [11]3 years ago

8 0

No clu ehow that would work ou tdoesnt make sense

ycow [4]3 years ago

3 0

Lucas's fruit bar was bigger than Stella's fruit bar...Hope this helped

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find the equation in slope intercept form of a line that is a perpendicular bisector of segment AB with endpoints A(-5,5) and B(

aliina [53]

The equation in slope intercept form of a line that is a perpendicular bisector of segment AB with endpoints A(-5,5) and B(3,-3) is y = x + 2

<h3><u>Solution:</u></h3>

Given, two points are A(-5, 5) and B(3, -3)

We have to find the perpendicular bisector of segment AB.

Now, we know that perpendicular bisector passes through the midpoint of segment.

<em><u>The formula for midpoint is:</u></em>

$\text { midpoint }=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

$Here x_1 = -5 ; y_1 = 5 ; x_2 = 3 ; y_2 = -3$

$\text { So, midpoint of } A B=\left(\frac{-5+3}{2}, \frac{5+(-3)}{2}\right)=\left(\frac{-2}{2}, \frac{2}{2}\right)=(-1,1)$

<em><u>Finding slope of AB:</u></em>

$\text { Slope of } A B=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$\text { Slope } m=\frac{-3-5}{3-(-5)}=\frac{-8}{8}=-1$

We know that product of slopes of perpendicular lines = -1

So, slope of AB $\times$ slope of perpendicular bisector = -1

- 1 $\times$ slope of perpendicular bisector = -1

Slope of perpendicular bisector = 1

We know its slope is 1 and it goes through the midpoint (-1, 1)

<em><u>The slope intercept form is given as:</u></em>

y = mx + c

where "m" is the slope of the line and "c" is the y-intercept

Plug in "m" = 1

y = x + c ---- eqn 1

We can use the coordinates of the midpoint (-1, 1) in this equation to solve for "c" in eqn 1

1 = -1 + c

c = 2

Now substitute c = 2 in eqn 1

y = x + 2

Thus y = x + 2 is the required equation in slope intercept form

7 0

4 years ago

What is the completely factored out form of d^4-8d^2+16

Lostsunrise [7]

d^4-8d^2+16

(d^2-4d)(d^2-4d)

(d-2)(d+2)(d-2)(d+2)

Option D is correct

8 0

3 years ago

The number of measles cases increased 10.2% to 58 cases this year, what was the number of cases prior to the increase? (Express

jok3333 [9.3K]

Answer:

There were approximately 53 cases of measles before the increase.

Step-by-step explanation:

Since there was an increase of 10.2% this means that the value we have now is the value we had prior plus the increase, in other words this is 100% of the cases before the increase plus 10.2%, so we have now 110.2% of cases. We know that this value represents 58 cases, so we can use a rule of three in order to determine the prior value. This is seen bellow:

100% -> x

110.2% -> 58

110.2*x = 100*58

x = 5800/110.2 = 52.63

Which is approximately 53 cases.

8 0

3 years ago