Answer:
-8>x>6
Step-by-step explanation:
I 5x+5I +22> 57subtract 22 on both sides
I5x+5I >35
SPLIT
5x+5>35 5x+5< -35 ( flip sign and 35 negative)
5x>30 5x< -40
x>6 x< -8
Draw a number line Write zero in the middle
From zero count to the left until- 8 make an open circle because- 8 is not included From -8 draw an arrow to the left (because x is less than -8)
From zero count to the right until 6 Make an open circle bc 6 is not included. From 6 draw an arrow to the right (because x is more than 6)
PART 2 is not already solved?
If you need to solve fot t
Divide both parts by pr
t= (l/ pr)
The intersection of the steps is just a fancy way of asking wi\hich numbers are in both equations so lets look and see :)
The 1st = 0...1...5...7...8
The 2nd =0........5...7........9
Answer = D {0, 5, 7}
Hope this helps have any questions let me know :)
Answer: 68400
Explanation: The question is asking for area so you do base times height. In this case you multiply 360 times 190.
Given:
The function is

To find:
The asymptotes and zero of the function.
Solution:
We have,

For zeroes, f(x)=0.



Therefore, zero of the function is 0.
For vertical asymptote equate the denominator of the function equal to 0.


Taking square root on both sides, we get


So, vertical asymptotes are x=-4 and x=4.
Since degree of denominator is greater than degree of numerator, therefore, the horizontal asymptote is y=0.