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finlep [7]
3 years ago
10

Enter an inequality that represents the graph in the box.

Mathematics
1 answer:
Vladimir [108]3 years ago
3 0

Answer:

It will be -8≤×≤8

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Answer:

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4 years ago
Gwen says that the sum of -1 3/4 and 2 1/2 is the same as the difference between 2 1/2 and 1 3/4. Is Gwen correct? Explain why o
solong [7]

Answer: No

Step-by-step explanation: no because one is negative 1 3/4 and the other one isint in the negatives

4 0
3 years ago
Help me, please this isn't really so hard, but I really need help
Oxana [17]

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3 years ago
Judy worked 8 hours and Ben worked 10 hours. Their combined pay was $80. When Judy worked 9 hours and Ben worked 5 hours, their
pav-90 [236]

Answer:

Judy = $5/hr

Ben = $4/hr

Step-by-step explanation:

Judy's hours at work - x

Ben's hours at work - y

8x + 10y = 80

9x + 5y = 65

Given these two equations above, we get:

10y = 80 - 8x, which means y = 8 - 0.8x.

Substitute y in the second equation with 8 - 0.8x, so we have:

9x + 5 (8 - 0.8x) = 65

9x + 40 - 4x = 65

5x = 25

x = 5

Come back to the first equation, substitute x:

8*5 + 10y = 80

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y = 4

3 0
3 years ago
The area of a rectangle is the rectangle’s length times its width. Write a program that asks for the length and width of two rec
Mnenie [13.5K]

Answer:

Using c++

Check the image for colors.

Step-by-step explanation:

#include <iostream>

using namespace std;

int main()

{

   float length1,length2,width1,width2,area1,area2;

   

   cout<<"length of Rectangle 1\n";

   cin>>length1;

   cout<<"\nwidth of Rectangle 1\n";

   cin>>width1;

   cout<<"\nlenght of Rectangle 2\n";

   cin>>length2;

   cout<<"\nwidth of Rectangle 2\n";

   cin>>width2;

   

   area1=length1*width1;

   area2=length2*width2;

   

   if (area1<area2)

   {cout << "\nRectangle 2 has greater area";}

   else {

               if (area1>area2)

                  {cout << "\nRectangle 1 has greater area";}

               else {cout << "\nAreas are the same";}

         }

   

   return 0;

}

7 0
3 years ago
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