Number 13 please.it’s the answe.r

Mathematics

1 answer:

gizmo_the_mogwai [7]2 years ago

3 0

The answer is there what u need help with?

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3. Solve the inequality –2(z + 5) + 20 > 6.

12345 [234]

$\boxed{-2\left(z+5\right)+20>6\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:z$

Solution:

Given inequality is:

$-2(z+5)+20>6$

We have to solve the given inequality

$-2\left(z+5\right)+20>6\\\\\mathrm{Subtract\:}20\mathrm{\:from\:both\:sides}\\\\-2\left(z+5\right)+20-20>6-20\\\\\mathrm{Simplify}\\\\-2\left(z+5\right)>-14$

$Multiply\ both\ sides\ by\ -1\ \left(reverse\:the\:inequality\right)$

Whenever we multiply or divide an inequality by a negative number, we must flip the inequality sign

$\left(-2\left(z+5\right)\right)\left(-1\right)$

Thus the solution to inequality is:

$-2\left(z+5\right)+20>6\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:z$

4 0

3 years ago

Find the values of x and y for which ABCD must be a parallelogram.?

Semmy [17]

2x - 2 = x + 2
2x - x = 2 + 2 = 4
x = 4

5y - 8 = y + 24
5y - y = 24 + 8
4y = 32
y = 8.

7 0

3 years ago

Read 2 more answers

13. Find the vertex of f(x)=x2 -6x +8 .

Mekhanik [1.2K]

9514 1404 393

Answer:

a (3,-1)

Step-by-step explanation:

The number that "completes the square" is the square of half the x-coefficient, (-6/2)^2 = 9. Rearranging the given function to include the square trinomial, we have ...

f(x) = x^2 -6x +9 -1 . . . . . . . here, we have 8 = 9 - 1

f(x) = (x -3)^2 -1 . . . . . . . . . . vertex form

Comparing this to the generic vertex form ...

f(x) = (x -h)^2 +k . . . . . . . vertex at (h, k)

we see that h=3 and k=-1.

The vertex is (h, k) = (3, -1).