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Juliette [100K]
2 years ago
12

Divide. 5 divided by 1/4 PLS HELP

Mathematics
2 answers:
likoan [24]2 years ago
6 0

Answer:

20 bro

Step-by-step explanation:

kiruha [24]2 years ago
6 0

Answer :

20 It Got Deleted

◊ YusuCr ◊

:)

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Evaluate the expression 8n for n = 1 5/12
ad-work [718]

Answer

8n=34/3

Step-by-step explanation:

1 5/12=17/12

17/12*8/1=136/12=34/3

4 0
2 years ago
Evaluate f(t)=-2t^2+ 1 for f(-3). PLEASE HELP I BEG YOU!!!!!!!!!!!
choli [55]

Answer:

f(-3)=-17

Step-by-step explanation:

→ Substitute in t = -3 into f(t)=-2t^{2} +1

f(-3)=-2*-3^{2} +1

→ Simplify

f(-3)=-2*9 +1

→ Simplify

f(-3)=-18 +1 ⇔ f(-3)=-17

6 0
3 years ago
Add the equations.<br>2x-3y = -1<br>+ 3x + 3y= 26<br><br>​
hichkok12 [17]

Answer:

The answer in the procedure

Step-by-step explanation:

we have

2x-3y=-1 ----> equation A

3x+3y=26 --> equation B

Solve the system by elimination

Adds equation A and equation B

2x-3y=-1

3x+3y=26

----------------

2x+3x=-1+26

5x=25

x=25/5

x=5

Find the value of y

substitute the value of x in equation A or equation B and solve for y

2(5)-3y=-1

10-3y=-1

3y=10+1

y=11/3

8 0
3 years ago
PLEASE SOMEONE HELP I TRULY DO NOT UNDERSTAND
IceJOKER [234]

Hi there!

\large\boxed{f^{-1}(x) =  \sqrt[3]{\frac{x+4}{9} } }

f(x) = 9x^{3} - 4

Find the inverse by replacing f(x) with y and swapping the x and y variables:

x = 9y^{3} - 4

Isolate y by adding 4 to both sides:

x + 4 = 9y^{3}

Divide both sides by 9:

\frac{x+4}{9}= y^{3}

Take the cube root of both sides:

y = \sqrt[3]{\frac{x+4}{9} }\\\\f^{-1}(x) = \sqrt[3]{\frac{x+4}{9} }

7 0
3 years ago
The proof that point (1,root 3) lies on the circle that is centered at the origin and contains the point (0,2) is found in the t
AURORKA [14]
<h2>Answer:</h2>

D. Distance formula

<h2>Step-by-step explanation:</h2>

The \ \mathbf{distance} \ d \ between \ the \ \mathbf{points} \ (x_{1},y_{1}) \ and \ (x_{2},y_{2}) \ in \ the \ plane \ is:\\ \\ d=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

As in the statement:

<em>The distance form</em> (0,0) to (0,2) is \sqrt{(0-0)^2+(2-0)^2}=\sqrt{2^2}=2 <em>whose justification is the </em><em>Distance Formula. </em>

<em />

Here in this statement the justification is also the Distance Fromula, so we take the distance from (0,0) \ to \ (1,\sqrt{2}) whose result is also 2 and is the radius of the circle.

3 0
3 years ago
Read 2 more answers
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