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LenaWriter [7]
3 years ago
8

What is the solution to the system of equationsY=4x+11 and y =-2x-1

Mathematics
1 answer:
pav-90 [236]3 years ago
5 0

For this case we must solve a system of two equations with two unknowns, given by "x" and "y".

We have:

y = 4x + 11\ (1)\\y = -2x-1\ (2)

We multiply (2) by -1:

-y = 2x + 1\ (3)

We add (1) and (3):

y-y = 4x + 2x + 11 + 1\\0 = 6x + 12

Clearing x:

-12 = 6x\\x = \frac {-12} {6}\\x = -2

We substitute x = -2 in (2)

y = -2 (-2) -1\\y = 4-1\\y = 3

Thus, the solution of the system is (x, y) = (- 2,3)

Answer:

The solution of the system is (x, y) = (- 2,3)



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Find the area of a rhombus if its diagonals are of lengths 12.8 cm and 8.4cm
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Area =

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where p and q are it's diagonal

so according to the rule.

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is the answer.

<em><u>hope </u></em><em><u>understands </u></em>

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1 year ago
When an exponent is a negative number, we can think of it as taking the...?
STALIN [3.7K]

Answer:

We can think of it as the zeros after the decimal point.

Step-by-step explanation:

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3 years ago
Change the following subtraction expression to addition: 2 - 11
tester [92]

Answer:

I think it would be 2+ -11

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Figure ABCDE has vertices a(-3, 3), b(2, 3), c(5, -2), d(0, -3), and e(-3, -2). Plot the points on your own coordinates grid and
Ilya [14]
<h2>Answer:</h2>

Shown below

<h2>Step-by-step explanation:</h2>

First of all, we have the following points:

a(-3, 3) \\ \\ b(2, 3) \\ \\ c(5, -2) \\ \\ d(0, -3) \\ \\ e(-3, -2)

To plot these points, we need to graph a coordinate grid. Recall that a coordinate grid is composed of two perpendicular lines, that we call the axes and are labeled like number lines. The horizontal axis is called the x-axis while the vertical axis is called the y-axis, and these two axes intersect at a point called the origin. Next, let's plot each point as follows:

<h2>PART 1. Plot the points on your own coordinates grid and connect in alphabetical order. </h2><h2></h2>

Point a:

Let's stand at the origin and then move three units to the left and three units up. The resulting point is shown in the firs figure below.

Point b:

Let's stand at the origin and then move two units to the right and three units up. The resulting point is shown in the firs figure below.

Point c:

Let's stand at the origin and then move five units to the right and two units down. The resulting point is shown in the firs figure below.

Point d:

Let's stand at the origin and then move three units to down. The resulting point is shown in the firs figure below.

Point e:

Let's stand at the origin and then move three units to the left and two units down. The resulting point is shown in the firs figure below.

Next, let's connect connect the points in alphabetical order, so that the line are connected from a to b, from b to c, from c to d, from d to e and from e to a again. So the resulting graph is shown in the second figure. As you can see, this is an irregular pentagon.

<h2>PART 2. Decompose figure ABCDE into rectangles and triangles.</h2>

Every pentagon can be divided up into three triangles. Hence, from the third figure. the triangles are:

ΔABE

ΔBDE

ΔBCD

Since a rectangle is a quadrilateral whose angles are all right angles, then there is no chance to obtain a rectangle from ABCDE. To obtain a rectangle, we'd need other points and this is not what the problem asks.

5 0
3 years ago
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