Angel 3 is adjacent to Angel 4 therefore they are equal.
Let the first investment be x
and second be 3000-x
so 3%of x + 4% of (3000-x) = 107
By solving x = 1300
First investment is 1300
second investment is 1700
Given:
height = 6m
chord = 20 m
We need to find the radius of the circle.
20 m = 2 √ [ 6m( 2 x radius - 6 m ) ]
20 m / 2 = 2 √<span>[ 6m( 2 x radius - 6 m ) ] / 2 </span>
10 m = √<span> [ 6m( 2 x radius - 6 m ) ] </span>
(10 m)² = √[ 6m( 2 x radius - 6 m ) ] ²
100 m²<span> = 6 m( 2 x radius - 6 m ) </span>
100 m²<span> = 12 m x radius - 36 sq m </span>
100 m² + 36 m² = 12 m x radius - 36 m² + 36 m²
136 m²<span> = 12 m x radius </span>
136 m²<span> / 12 m = 12 m x radius / 12 m </span>
<span>11.333 m = radius
</span>
the area beneath an arc:
<span>Area = r</span>²<span> x arc cosine [ ( r - h ) / r ] - ( r - h ) x </span>√<span>( 2 x r x h - h</span>²<span> ).
</span>
<span>r</span>²<span> = (11.333 m)</span>²<span> = 128.444 m</span>²<span> </span>
<span>r - h= 11.333 m - 6 m = 5.333 m </span>
<span>r * h = 11.333 m x 6 m = 68 m</span>²
<span>Area = 128.444 m</span>²<span> x arc cosine [ 5.333 m / 11.333 m ] - 5.333 m x </span>√<span>[ 2 x 68 m</span>²<span> - 36 m</span>²<span> ] </span>
<span>Area = 128.444 m</span>²<span> x arc cosine [ 0.4706 ] - 5.333 m x </span>√<span> [ 100m</span>²<span> ] </span>
<span>Area = 128.444 m</span>²<span> x 1.0808 radians - 5.333 m x 10 m </span>
<span>Area = 138.828 m</span>²<span> - 53.333 m</span>²<span> </span>
<span>Area = 85.4 m</span>²
Answer:
∠A = 26°
Step-by-step explanation:
Supplementary angles total 180°.
∠A +∠B = 180°
(x -16)° +(3x +28)° = 180°
4x° + 12° = 180°
x° +3° = 45°
x° = 42°
∠A = (x -16)° = 42° -16°
∠A = 26°
brainliest please?
Not easy to graph but
multily first equaiton by -2 remember to flip sign
-2x+4y>-6
add to other equaiton
2x-2x+y+4y>-6+8
5y>2
divide by 5
y>2/5
subtitute
2x+2/5>8
subtract 2/5 from both sdies
2x>7 3/5
divid eby 2
x>38/10=19/5=3 4/5
x>3 4/5
y>2/5
just shade the area in that zone, not including point (0,0)
