Answer:
250 minutes of calling will cost same using both plans.
$53
Step-by-step explanation:
Please consider the complete question.
A phone company offers two monthly plans. Plan A costs $23 plus an additional $0.12 for each minute of calls. Plan B costs $18 plus an additional $0.14 of each minute of calls. For what amount of calling do the two plans cost the same? What is the cost when the two plans cost the same?
Let x represent the number of call minutes.
The total cost of calling for x minutes using plan A would be cost of x minutes plus fixed charge that is 
.
The total cost of calling for x minutes using plan B would be cost of x minutes plus fixed charge that is 
.
To find the number of minutes for which both plans will have same cost, we will equate total cost of x minutes for both plans and solve for x.
Therefore, calling for 250 minutes will cost same using both plans.
Upon substituting in expression , we will get:
Therefore, the cost will be $53, when the two plans cost the same.
Answer:
alternate exterior angles
Step-by-step explanation:
When two lines are crossed by another line (called the Transversal): Alternate Exterior Angles are a pair of angles on the outer side of each of those two lines but on opposite sides of the transversal.
<span>The trigonometric function cosecant is written as csc θ. For acute angles, csc θ can be found by the SOHCAHTOA definition, shown below on the left. The circle definition, a generalization of SOHCAHTOA, is shown below on the right. f(x) = csc x is a periodic function with period 2π.</span>
Answer:
Step-by-step explanation:
y e s , m e h f r i e n d
Step-by-step explanation:
a geometric sequence means that every term is created by multiplying the previous term by a certain constant factor. this factor is called the "common ratio".
so,
6×r = 18
r = 18/6 = 3
and a quick check tells us this works also for the next terms (18×3 = 54, 54×3 = 162), so it is indeed a geometric sequence with common ratio 3.
a0 = 6
a1 = a0 × 3 = 6×3 = 18
a2 = a1 × 3 = a0 × 3×3 = 6×3² = 54
an = a0 × 3^n = 6 × 3^n
so,
f(x) = 6×3^x, x is integer, x >=0
