All categories

2 years ago

SOMEONE PLEASE HELP I WILL MARK U BRAINLIST

Mathematics

1 answer:

mash [69]2 years ago

7 0

Answer:

x = 3

Step-by-step explanation:

$In\: \triangle PQT,\: \overline{PQ}|| \overline {RS}...(Given)\\\\\implies\frac{PS}{ST}=\frac{QR}{RT}\\(By\: Proportionality\: Theorem) \\ \\\implies\frac{2x+4}{5}=\frac{3x+5}{7}\\\\ \implies \: 7(2x + 4) = 5(3x + 5) \\ \\ \implies \:14x + 28 = 15x + 25 \\ \\ 14x - 15x = 25 - 28 \\ \\ - x = - 3 \\ \\ x = 3$

You might be interested in

A ball is thrown upward with an initial velocity of 96 ft/sec from a height 640 ft. Its height h, in feet, after t seconds is

olchik [2.2K]

Check the picture below.

thus is at 0 = -16t² + 96t +640,

$\bf 0=-16t^2+96t+640\implies 0=-16(t^2-6t-40)
\\\\\\
0=t^2-6t-40\implies 0=(t-10)(t+4)\implies t=
\begin{cases}
\boxed{10}\\
-4
\end{cases}$

well, clearly it can't be a negative value for the elapsed seconds, so it can't be -4.

5 0

3 years ago

(b+3)1/2+b1/2=3<br> A. b=0 and b= 2/3<br> B. b=1/4 and b=2<br> C. b=1<br> D. b=3

yan [13]

The answer is C Kay. Got it?

4 0

3 years ago

Solve y=f(x) for x. Then find the input when the output is -3.

DochEvi [55]

Answer:

Please check the explanation

Step-by-step explanation:

Given the function

$f\left(x\right)\:=\:\left(x-5\right)^3-1$

Given that the output = -3

i.e. y = -3

now substituting the value y=-3 and solve for x to determine the input 'x'

$\:\:y=\:\left(x-5\right)^3-1$

$-3\:=\:\left(x-5\right)^3-1\:\:\:$

switch sides

$\left(x-5\right)^3-1=-3$

Add 1 to both sides

$\left(x-5\right)^3-1+1=-3+1$

$\left(x-5\right)^3=-2$

$\mathrm{For\:}g^3\left(x\right)=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}$

Thus, the input values are:

$x=-\sqrt[3]{2}+5,\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}-i\frac{\sqrt[3]{2}\sqrt{3}}{2},\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}+i\frac{\sqrt[3]{2}\sqrt{3}}{2}$

And the real input is:

$x=-\sqrt[3]{2}+5$

$x=3.74$

4 0

3 years ago

Please help!! I need to know this by today

Fiesta28 [93]

9.42 I think its 9.42

4 0

3 years ago

A lottery consists of one $2000 winner, three $500 winners, and ten $100 winners. a total of 1000 tickets are sold for $10 each.

Semenov [28]

Answer: -5.5

WOKINGS

Given that the lottery has the following number of winners:

One $2000 winner

Three $500 winners

Ten $100 winners

Also Given,

A total of 1000 tickets are sold

Each ticket costs $10

The expected winning for a person purchasing one ticket is the sum of the products of the gain/loss and their corresponding probability.

There is one $2000 winner

There are 1000 tickets

The probability of winning $2000

= 1/1000

= .001

There are three $500 winners

There are 1000 tickets

The probability of winning $500

= 3/1000

= .003

There are ten $100 winners

There are 1000 tickets

The probability of winning $100

= 10/1000

= .01

Since each ticket costs $10

Everyone who buys a ticket automatically loses $10.

Therefore, the probability of losing $10 is 1

Now to calculate the expected winning for a person purchasing one ticket

= 2000(.001) + 500(.003) + 100(.01) – 10(1)

= 2 + 1.5 + 1 – 10

= -5.5

The expected winning is -5.5. This implies that a person playing this lottery can expect to lose $5.50 for every one ticket that they purchase.

7 0

3 years ago