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german
2 years ago
11

SOMEONE PLEASE HELP I WILL MARK U BRAINLIST

Mathematics
1 answer:
mash [69]2 years ago
7 0

Answer:

x = 3

Step-by-step explanation:

In\: \triangle PQT,\: \overline{PQ}|| \overline {RS}...(Given)\\\\\implies\frac{PS}{ST}=\frac{QR}{RT}\\(By\: Proportionality\: Theorem) \\ \\\implies\frac{2x+4}{5}=\frac{3x+5}{7}\\\\ \implies \: 7(2x + 4) = 5(3x + 5) \\  \\ \implies \:14x + 28 = 15x + 25 \\  \\ 14x - 15x = 25 - 28 \\ \\ - x =  - 3 \\  \\ x = 3

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ILL MARK BRAINLIST pls help
kaheart [24]

You cut out the question-

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2 years ago
2x / 2x is equals to?​
Bond [772]
It’s equal to 1

2x divide by 2x = 1
— —
2x divide by 2x 1

which equals to 1
5 0
3 years ago
Elysse paid for her lunch with a $10 bill and recieved 0.63 in change the lunch special was 7.75 sales tax was 0.47 what was the
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7 0
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Read 2 more answers
A convex figure has three sides what is the sum of its exterior angles
SashulF [63]

A convex figure with three sides is triangle. The sum of the measures of all interior angles of the triangle is 180°.

Let \alpha, \beta, \gamma be interior angles of this triangle. Then

\alpha+\beta+\gamma=180^{\circ}.

Find exterior angles of this triangle:

1. 180^{\circ}-\alpha is exterior angle adjacent to the interior angle \alpha.

2. 180^{\circ}-\beta is exterior angle adjacent to the interior angle \beta.

3. 180^{\circ}-\gamma is exterior angle adjacent to the interior angle \gamma.

The sum of the measures of all exterior angles is

180^{\circ}-\alpha+180^{\circ}-\beta+180^{\circ}-\gamma=540^{\circ}-(\alpha+\beta+\gamma)=540^{\circ}-180^{\circ}=360^{\circ}.

Answer: 360°

4 0
3 years ago
Use the properties of 30-60-90 and 45-45-90 triangles to solve for x in each of the problems below. Then decode the secret messa
murzikaleks [220]

The trigonometric function gives the ratio of different sides of a right-angle triangle. The given problems can be solved as given below.

<h3>What are Trigonometric functions?</h3>

The trigonometric function gives the ratio of different sides of a right-angle triangle.

\rm Sin \theta=\dfrac{Perpendicular}{Hypotenuse}\\\\\\Cos \theta=\dfrac{Base}{Hypotenuse}\\\\\\Tan \theta=\dfrac{Perpendicular}{Base}\\\\\\Cosec \theta=\dfrac{Hypotenuse}{Perpendicular}\\\\\\Sec \theta=\dfrac{Hypotenuse}{Base}\\\\\\Cot \theta=\dfrac{Base}{Perpendicular}\\\\\\

where perpendicular is the side of the triangle which is opposite to the angle, and the hypotenuse is the longest side of the triangle which is opposite to the 90° angle.

1st.) x = 5 /Sin(30°)

x = 10

!) sin(45°) = 4/x

x = 4/sin(45°)

x = 4√2

I) Cos(45°) = √3 / x

x = √3 / Cos(45°)

x = √6

E) Tan(60°) = 3√3 / x

x = 3√3 / 3

W) For isosceles right-triangle, the angle made by the legs and the hypotenuse is always 45°.

x = 45°

N) x² + x² = (7√2)²

x = 7

V) Tan(60°) = 7 / x

x = 7√3/3

K) x² + x² = (9)²

x = 9/√2

Y) Sin(60°) = 7√3/x

x = 14

M) Sin(30°) = x/11

x = 11/2

T) Sin(45°) = x/√10

x = √5

A) x + 2x + 90° = 180°

x = 30°

O) Sin(45°) = √2 / x

x = 2

R) Tan(30°) = x / 4

x = 4/√3 = 4√3 / 3

S) Sin(60°) = x / (10/3)

x = 5√3 / 3

Learn more about Trigonometric functions:

brainly.com/question/6904750

#SPJ1

5 0
1 year ago
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