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Bond [772]
2 years ago
15

Theoretically if a card is chosen 200 times, how many times would you expect to get a card without stripes?

Mathematics
1 answer:
steposvetlana [31]2 years ago
3 0

Answer:

5

Step-by-step explanation:

200/2=100 then after 100 u divide card by 2 so 100/2 and that's 50 and then last divide by 10 because its the circumference so its 5

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Solve this quadratic equation using the quadratic formula. 2x 2 - 10x + 7 = 0
sladkih [1.3K]

Answer:X=11/10

Step-by-step explanation:

2x2-10x+7=0

<u><em>4</em></u>-10x+<u><em>7</em></u>=0

11-10x=0

-10x= -11

Divide both side by -10

-10x/-10.  -11/-10

Answer= 11/10

7 0
3 years ago
Read 2 more answers
Solve. Write the solution in interval notation. -2x&gt;-8 and -5x&lt;20.
Novosadov [1.4K]

Answer:

The interval notation of the solution is (-4 , 4)

Step-by-step explanation:

* Let us explain a very important point in solving inequality

- When you multiply or divide an inequality by negative number we

   must reverse the symbol of the inequality

- Ex:

∵ 2 < 3

- If we multiply the both sides of the inequality by -1, then the

  inequality will be -2 < -3 and this is completely wrong, so we must

  reverse the symbol of the inequality

∴ -2 > -3

* Now let us solve the problem

∵ -2x > -8

- Divide both sides by -2 and remember to reverse the symbol of the

  inequality

∴ x < 4

∵ -5x < 20

- Divide both sides by -5 and remember to reverse the symbol of the

  inequality

∴ x > -4

- From both solutions

∴ -4 < x < 4

∴ The solution is {x : -4 < x < 4}

- Interval notation is a way of writing the solutions of inequalities

 ( , ) if x does not equal the end numbers

 [ , ] if x equals the end numbers

 [ , ) , ( , ] if x equals one of the two end numbers

* The interval notation of the solution is (-4 , 4)

4 0
3 years ago
A college infirmary conducted an experiment to determine the degree of relief provided by three cough remedies. Each cough remed
KiRa [710]

Answer:

p_v = P(\chi^2_{4,0.05} >3.81)=0.43233

Since the p values is higher than the significance level we FAIL to reject the null hypothesis at 5% of significance, and we can conclude that we don't have significant differences between the 3 remedies analyzed. So we can say that the 3 remedies ar approximately equally effective.

Step-by-step explanation:

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Assume the following dataset:

                               NyQuil          Robitussin       Triaminic     Total

No relief                    11                     13                      9               33

Some relief               32                   28                     27              87

Total relief                7                       9                      14               30

Total                         50                    50                    50              150

We need to conduct a chi square test in order to check the following hypothesis:

H0: There is no difference in the three remedies

H1: There is a difference in the three remedies

The level os significance assumed for this case is \alpha=0.05

The statistic to check the hypothesis is given by:

\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}

The table given represent the observed values, we just need to calculate the expected values with the following formula E_i = \frac{total col * total row}{grand total}

And the calculations are given by:

E_{1} =\frac{50*33}{150}=11

E_{2} =\frac{50*33}{150}=11

E_{3} =\frac{50*33}{150}=11

E_{4} =\frac{50*87}{150}=29

E_{5} =\frac{50*87}{150}=29

E_{6} =\frac{50*87}{150}=29

E_{7} =\frac{50*30}{150}=10

E_{8} =\frac{50*30}{150}=10

E_{9} =\frac{50*30}{150}=10

And the expected values are given by:

                               NyQuil          Robitussin       Triaminic     Total

No relief                    11                     11                       11               33

Some relief               29                   29                     29              87

Total relief                10                     10                     10               30

Total                         50                    50                    50              150

And now we can calculate the statistic:

\chi^2 = \frac{(11-11)^2}{11}+\frac{(13-11)^2}{11}+\frac{(9-11)^2}{11}+\frac{(32-29)^2}{29}+\frac{(28-29)^2}{29}+\frac{(27-29)^2}{29}+\frac{(7-10)^2}{10}+\frac{(9-10)^2}{10}+\frac{(14-10)^2}{10} =3.81

Now we can calculate the degrees of freedom for the statistic given by:

df=(rows-1)(cols-1)=(3-1)(3-1)=4

And we can calculate the p value given by:

p_v = P(\chi^2_{4,0.05} >3.81)=0.43233

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(3.81,4,TRUE)"

Since the p values is higher than the significance level we FAIL to reject the null hypothesis at 5% of significance, and we can conclude that we don't have significant differences between the 3 remedies analyzed.

4 0
3 years ago
Please hurry i need help and im stuck!!! helpsosososos
sammy [17]

Answer:

2

Step-by-step explanation:

the x and y are being multiplied by 2 e.g. 1 × 2 is 2 and 2 × 2 is 4 so the constant is 2

7 0
3 years ago
Read 2 more answers
Find the scale factor of the smaller figure to the larger figure
guapka [62]

Answer:

#9: 1.2

#10: 1.25

Step-by-step explanation:

To find the scale factor of the smaller figure to the larger figure, we're going to be dividing the measurements of corresponding edges.

\frac{larger figure}{smaller figure}

If you wanted to find the scale factor of the larger figure to the smaller figure, you'd do: \frac{smaller figure}{larger figure}

Question #9:

Left edges: \frac{larger figure}{smaller figure} ⇒ \frac{24}{20} = 1.2

Bottom edges: \frac{larger figure}{smaller figure} ⇒ \frac{30}{25} = 1.2

<em>(You should get the same number as long as the figures are similar.)</em>

<em />

Question #10:

Bottom edges: \frac{larger figure}{smaller figure} ⇒ \frac{30}{24} = 1.25

<em>(There are no corresponding edges with measurements that we can compare.)</em>

<em />

~Hope this helps!~

4 0
3 years ago
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