Question

423

Answer 1

Answer:

x³ - 3x² + 10x + 3 + $\frac{6}{x^4-4x^3+13x^2-7x+3}$

Step-by-step explanation:

Using synthetic division to divide by x - 1

 1  |  1   - 4   13   - 7   3

       ↓   1     - 3  10    3

    ----------------------------

       1  - 3    10    3    6 ← remainder = 6

      --------------------

               ↑ quotient

$\frac{x^4-4x^3+13x^2-7x+3}{x-1}$ = x³ - 3x² + 10x + 3 + $\frac{6}{x^4-4x^3+13x^2-7x+3}$