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Paha777 [63]
4 years ago
11

ormula1" title="3x - 2 \div 6x ^{2} + 11 ^{2} - 4x - 4" alt="3x - 2 \div 6x ^{2} + 11 ^{2} - 4x - 4" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
RoseWind [281]4 years ago
4 0

3 - 2 \div 6 \times 2 + 11 \times 2 - 4 - 4
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Consider the parametric curve:
11Alexandr11 [23.1K]

By the chain rule,

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm dt}}{\frac{\mathrm dx}{\mathrm dt}}=\dfrac{4\sec t\tan t}{3\sec^2t}=\dfrac43\sin t

When t=\pi, we have

\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{t=\pi}=\dfrac43\sin\pi=0

7 0
3 years ago
... If g(x)= x^2 + 3x, what is the value of g(-3).<br> (1) 0<br> (3) 18<br> (2)3<br> (4) 21
diamong [38]

Answer:

g(-3) = 0

Step-by-step explanation:

hello :

g(-3) = (-3)² + 3(-3) = 9-9 =0

3 0
3 years ago
For what value of a does (1/9)a+1 =81a+1 272-a?
AlexFokin [52]

Answer:

-4

Step-by-step explanation:

\left( \dfrac{1}{9}\right)^{a+1}= 81^{a+1}\cdot 27^{2-a}\\\\\\(3^{-2})^{a+1}=(3^4)^{a+1}\cdot (3^3)^{2-a} \\\\\\3^{-2a-2}=3^{4a+4}\cdot 3^{6-3a} \\\\\\3^{-2a-2}=3^{a+10} \\\\\\-2a-2=a+10 \\\\\\-3a=12 \\\\\\a=-4

Hope this helps!

8 0
3 years ago
Paulo’s grandfather gave him a collection of 20 coins. Each month Paulo adds 4 coins to his collection. Which inequality can be
Phoenix [80]

Answer:

4m+20>50

Step-by-step explanation:

Let <em>m</em> represent the amount of months that has passed.

Paulo started out with 20 coins.

Each month, he adds four more coins to his collection.

Therefore, the amount of coins added after <em>m</em> months will be given by 4<em>m</em>.

So, the amount of coins Paulo has total after <em>m</em> months can be given by:

4m+20

We want to know when Paulo will have "more than" 50 coins in his collection. Therefore, we will use the "greater than" sign. Thus, our inequality will be:

4m+20>50

4 0
3 years ago
I need help with this question
Mila [183]

Answer:

14 is the answer

Step-by-step explanation:

f = 2

e - 2 x 1/2 = e - 1

e = 15

15 - 1 = 14

3 0
3 years ago
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