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Paha777 [63]
3 years ago
11

ormula1" title="3x - 2 \div 6x ^{2} + 11 ^{2} - 4x - 4" alt="3x - 2 \div 6x ^{2} + 11 ^{2} - 4x - 4" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
RoseWind [281]3 years ago
4 0

3 - 2 \div 6 \times 2 + 11 \times 2 - 4 - 4
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Simplify.<br><br> 6x+4y-4x+5y+5
riadik2000 [5.3K]

Answer:

2x + 9y + 5

Step-by-step explanation:

Combine like terms:

(6x - 4x) + (4y + 5y) + 5

2x + 9y + 5

5 0
3 years ago
A student has gotten the following grades on his tests. What is the minimum grade he must get on the last test in order to have
likoan [24]

72 is the minimum grade he must get on the last test in order to have an average of 77.

<u>Step-by-step explanation:</u>

The grades of a student are given 72,91,78,72 and the grade of his last test is not given.

  • You have to find the minimum grade the student shall get, so that the student average must be 77.
  • The four grades are already given. Therefore, we need to find only the fifth grade.

The term average is defined as the sum of all the data in a set divided by the number of data in a set.

Here, the number of data is 5. (Because the students has 4 grades plus one grade for his last test).

The average he should get is 77.

Average = Sum of all grades / number of grades

Let, 'x' be the grade of the last test.

⇒ 77 = (72+91+78+72+x) / 5

⇒ 77 = (313+x) / 5

⇒ 385 = 313 + x

⇒ x = 385 - 313

⇒ x = 72

The minimum grade he must get on the last test is 72.

5 0
3 years ago
Which statement is true
slava [35]
C.) because red is g and it goes up 6 right 6 an since blue is F it goes up 3 right 3 which would collide at the center
8 0
3 years ago
Read 2 more answers
Given: <br> PQ<br> ⊥<br> QR<br> , PR=20,<br> SR=11, QS=5<br> Find: The value of PS.
dlinn [17]

Answer:

The value of the side PS is 26 approx.

Step-by-step explanation:

In this question we have two right triangles. Triangle PQR and Triangle PQS.

Where S is some point on the line segment QR.

Given:

PR = 20

SR = 11

QS = 5

We know that QR = QS + SR

QR = 11 + 5

QR = 16

Now triangle PQR has one unknown side PQ which in its base.

Finding PQ:

Using Pythagoras theorem for the right angled triangle PQR.

PR² = PQ² + QR²

PQ = √(PR² - QR²)

PQ = √(20²+16²)

PQ = √656

PQ = 4√41

Now for right angled triangle PQS, PS is unknown which is actually the hypotenuse of the right angled triangle.

Finding PS:

Using Pythagoras theorem, we have:

PS² = PQ² + QS²

PS² = 656 + 25

PS² = 681

PS = 26.09

PS = 26

7 0
3 years ago
A cuboid with dimensions 45 cm by 16 cm by 12 cm is cut to form smaller cubes of
LenKa [72]

Answer:

<u>135 cubes</u>

Step-by-step explanation:

Volume of cuboid :

  • 45 x 16 x 12
  • 720 x 12
  • 8,640 cm³

Volume of a small cube :

  • (4)³
  • 64 cm³

Number of cubes :

  • n = 8,640/64
  • n = <u>135 cubes</u>
4 0
2 years ago
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