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V125BC [204]
2 years ago
12

1. The below ratios form a proportion. Please help me. ​

Mathematics
2 answers:
DedPeter [7]2 years ago
7 0

Answer:

true

Step-by-step explanation:

CaHeK987 [17]2 years ago
4 0

Answer:

true

Step-by-step explanation:

it's true because it's a proportion

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Use "complete the square" to find the missing value: <br>x^2-18x+___?
worty [1.4K]

Answer:

81

Step-by-step explanation:

x^2 - 18x + _______

to find the blank

take (b/2) ^2

where b is the coefficient on the x term

(-18/2) ^2

9^2

81

add 81

8 0
4 years ago
Which of the following would not be a correct interpretation of a correlation of r = .35?
Nikitich [7]
Even though it may look like the option is E the real answer is that the variables are invesely related. So your answer will be D
8 0
3 years ago
A bag contains 100 apples, 100 bananas, 100 oranges, and 100 pears. If I pick one piece of fruit out of the bag every minute, ho
k0ka [10]

Answer:

required time is here 45 minutes

Step-by-step explanation:

given data

apples = 100

bananas = 100

oranges = 100

pears = 100

solution

we have here 4 different kind of fruit

so that it is possible for each kind of fruit is

each kind of fruit is = 4 × 11  = 44

so each kind contain 11  fruit

as that 45th fruit make a dozen

now 1 fruit is pick every minute

'so we take here 45 minute to pick up 45 fruit

so that required time is here 45 minutes

5 0
3 years ago
I WILL GIVE BRAINLIEST TT
Vinil7 [7]

Answer:

2

Step-by-step explanation:

Yeah its 2 I can explain but will be long but if want comment and I will post but most likely its 2

3 0
3 years ago
9.4 The heights of a random sample of 50 college stu- dents showed a mean of 174.5 centimeters and a stan- dard deviation of 6.9
gladu [14]

Answer:  a) (176.76,172.24), b) 0.976.

Step-by-step explanation:

Since we have given that

Mean height  = 174.5 cm

Standard deviation = 6.9 cm

n = 50

we need to find the 98% confidence interval.

So, z = 2.326

(a) Construct a 98% confidence interval for the mean height of all college students.

x\pm z\times \dfrac{\sigma}{\sqrt{n}}\\\\=(174.5\pm 2.326\times \dfrac{6.9}{\sqrt{50}})\\\\=(174.5+2.26,174.5-2.26)\\\\=(176.76,172.24)

(b) What can we assert with 98% confidence about the possible size of our error if we estimate the mean height of all college students to be 174.5 centime- ters?

Error would be

\dfrac{\sigma}{\sqrt{n}}\\\\=\dfrac{6.9}{\sqrt{50}}\\\\=0.976

Hence, a) (176.76,172.24), b) 0.976.

8 0
3 years ago
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