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3 years ago

9

Will mark BRAINEST!!! Solve for X

1 answer:

ArbitrLikvidat [17]3 years ago

4 0

Answer:

7

Step-by-step explanation:

it is 7 pimp ..... dj rice dh ended duvdir di r r

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Lisa decided to buy a new car and the dealership told her that she had to give them 6% of the sales price as a down payment. If

Stels [109]

Selling price = 100%. = $18,000
1%= $18,000/100 = $180
6% = 6 x 1% = 6 x $180 =$1,080.

Down payment = $1,080

6 0

4 years ago

Read 2 more answers

Factorise 6x² -5x -21

Alex Ar [27]

I think it’s this but I’m not sure

5 0

3 years ago

Two distinct number cubes, one red and one blue, are rolled together. Each number cube has sides numbered 1 through 6.

cestrela7 [59]

Answer:

$P(E_1 or E_2) = \frac{7}{12}$

Step-by-step explanation:

Given

Two cubes of side 1 - 6

Required

Probability that the outcome of the roll is an odd sum or a sum that is a multiple of 5

First, the sample space needs to be listed;

Let $C_r$ represent the Red cube

$C_b$ represent the Blue cube

S represent the sample space

$C_r = (1,2,3,4,5,6)\\C_b = (1,2,3,4,5,6)\\S = (2,3,4,5,6,7,3,4,5,6,7,8,4,5,6,7,8,9,5,6,7,8,9,10,6,7,8,9,10,11,7,8,9,10,11,12)$ S is gotten by getting the sum of $C_r$ and $C_b$

$n(S) = 36$

<em>Calculating the Probability</em>

Let $E_1$ represent the event that an outcome is an odd sum

$E_1 = (3,5,7,3,5,7,5,7,9,5,7,9,7,9,11,7,9,11)$

$n(E_1) = 18$

$P(E_1) = \frac{n(E_1)}{n(S)}$

$P(E_1) = \frac{18}{36}$

Let $E_2$ represent the event that an outcome is a multiple of 5

$E_2 = (5,5,5,5,10,10,10)$

$n(E_2) = 7$

$P(E_2) = \frac{n(E_2)}{n(S)}$

$P(E_2) = \frac{7}{36}$

Let $E_3$ represent the event that an outcome is an odd sum and a multiple of 5

$E_3 = E_1 and E_2$

$E_3 = (5,5,5,5)$

$n(E_3) = 4$

$P(E_3) = \frac{n(E_3)}{n(S)}$

$P(E_3) = \frac{4}{36}$

Calculating $P(E_1 or E_2)$

$P(E_1 or E_2) = P(E_1) + P(E_2) - P(E_1 and E_2)$

$P(E_1 or E_2) = P(E_1) + P(E_2) - P(E_3)$

$P(E_1 or E_2) = \frac{18}{36} + \frac{7}{36} - \frac{4}{36}$

$P(E_1 or E_2) = \frac{18 + 7 - 4}{36}$

$P(E_1 or E_2) = \frac{21}{36}$

$P(E_1 or E_2) = \frac{7}{12}$

Hence, the probability that the outcome of the roll is an odd sum or a sum that is a multiple of 5 is $\frac{7}{12}$

6 0

3 years ago

Put 9, -7, and -8 in order from least to greatest. You can use the number line to help. 9 -10 -8 -7 -6 -8 -4 -2 0 2 4 6 8 10

boyakko [2]

-8, -7, 9

Step-by-step explanation:

8 0

2 years ago

Dad has 47 years. Son has 13 years. After how many years dad will be tree times older then his son?

Vadim26 [7]

Answer:

4 years.

Step-by-step explanation:

Let the number of years be x, then:

x + 47 = 3(x + 13)

x + 47 = 3x + 39

3x - x = 47-39

2x = 8

x = 4.

6 0

3 years ago

Read 2 more answers