The formula to find the volume of cube

cube = s^3

Therefore volume is equal to I^3

The second cube has 4x the First cube

4 × (I^3) = 4 ×I^3

Total volume of the second cube= 4I^3 cm3

Fact: the density(mass ÷ volume) of aluminium is 2.40g/cm3

Making mass the subject of the formula:

D = M ÷ V
(Times volume to remove deno minator)

Mass = Density × Volume

Mass = 2.40 × 4I ^3

Mass = 8.40I^3

By physics

weight= m × g

where
M = mass
g = acceleration due to gravity (= 9.8)

W = 8.40 I^3 × 9.8

Weight of aluminium = 82.32I^3

3 0

4 years ago

Use | = PRT to solve. (time is in years) P = $2,000 R = 15% Find I. T = 2 years

irga5000 [103]

Answer:

$600

Step-by-step explanation:

I = 2000(.15)(2)

I = 600

6 0

3 years ago

If p varies directly as q and q= 70 when p= 10, find q when p = 12

stellarik [79]

$\qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad \stackrel{\textit{constant of variation}}{y=\stackrel{\downarrow }{k}x~\hfill } \\\\ \textit{\underline{x} varies directly with }\underline{z^5}\qquad \qquad \stackrel{\textit{constant of variation}}{x=\stackrel{\downarrow }{k}z^5~\hfill } \\\\[-0.35em] ~\dotfill$

$\stackrel{\textit{"p" varies directly as "q"}}{p~~ = ~~kq}\qquad \textit{we also know that} \begin{cases} q=70\\ p=10 \end{cases}\implies 10=k70 \\\\\\ \cfrac{10}{70}=k\implies \cfrac{1}{7}=k\hspace{15em}\boxed{p=\cfrac{1}{7}k} \\\\\\ \textit{when p = 12, what is "q"?}\qquad 12=\cfrac{1}{7}q\implies 12=\cfrac{q}{7}\implies 84=q$

5 0

1 year ago