Solve the equation square root X-6+2 = 6 for the variable. Show each step of your solution process

1 answer:

3 0

The first step would be to isolate the square root on the left side. √x-6+2 = 6 √x-6 = -2+6 √x-6 = 4We would have to take away the radical on the left and square the equation. (√x-6)2 = (4)2 x-6 = 16Finally, x -22 = 0 x = 22

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Zahin has 4/6

LenKa [72]

Answer:

2/15 or 0.13

Step-by-step explanation:

first you multiply 2/3 and 1/5 which gets you 2/15

7 0

3 years ago

Read 2 more answers

I can't figure this out

andriy [413]

Suppose that equation of parabola is
y =ax² + bx + c

Since parabola passes through the point (2,−15) then
−15 = 4a + 2b + c

Since parabola passes through the point (-5,-29), then
−29 = 25a − 5b + c

Since parabola passes through the point (−3,−5), then
−5 = 9a − 3b + c

Thus, we obtained following system:
4a + 2b + c = −15
25a − 5b + c = −29
9a − 3b + c = −5

Solving it we get that
a = −2, b = −4, c = 1

Thus, equation of parabola is
y = −2x²− 4x + 1

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Rewriting in the form of
(x - h)² = 4p(y - k)

i) -2x² - 4x + 1 = y

ii) -3x² - 7x = y - 11
(-3x² and -7x are isolated)

iii) -3x² - 7x - 49/36 = y - 1 - 49/36
(Adding -49/36 to both sides to get perfect square on LHS)

iv) -3(x² + 7/3x + 49/36) = y - 3
(Taking out -3 common from LHS)

v) -3(x + 7/6)² = y - 445/36

vi) (x + 7/6)² = -⅓(y - 445/36)
(Shifting -⅓ to RHS)

vii) (x + 1)² = 4(-1/12)(y - 445/36)
(Rewriting in the form of 4(-1/12) ; This is 4p)

So, after rewriting the equation would be -

(x + 7/6)² = 4(-⅛)(y - 445/36)

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I hope this is what you wanted.

Regards,
Divyanka♪
__________________

6 0

3 years ago

Read 2 more answers

How do you solve for y in the equation: x/y = y - 6

I am Lyosha [343]

Answer:

x= y^2 -6y

Step-by-step explanation:

7 0

3 years ago

Someone please help me 4(d + 6) =

zaharov [31]