3 years ago

Triangle Inequality Theorem Ordering Angles & Sides of a Triangle - Geometry

Mathematics

1 answer:

Gemiola [76]3 years ago

4 0

Triangle axiom theorems : 76
Y=6
X=9

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Resiprocal of (-3/7)^2!

USPshnik [31]

Answer:

$\frac{49}{9}$

Step-by-step explanation:

Given

$(\frac{-3}{7})^{2!}$

Required

Determine the reciprocal

If a number is x, the reciprocal is: 1/x

So, the reciprocal of $(\frac{-3}{7})^{2!}$ is:

$\frac{1}{(\frac{-3}{7})^{2!}}$

$2! = 2*1 =2$

So, we have:

$\frac{1}{(\frac{-3}{7})^{2}}$

$\frac{1}{(\frac{-3^{2}}{7^{2}})}$

Evaluate all exponents

$\frac{1}{(\frac{9}{49})}$

Take inverse of 9/49

$\frac{49}{9}$

Hence, the reciprocal of $(\frac{-3}{7})^{2!}$ is $\frac{49}{9}$

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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