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yuradex [85]
2 years ago
12

If a^2-5a+1=0,what is the value of a^2-1/(a)^2​

Mathematics
1 answer:
mr_godi [17]2 years ago
4 0
-9-3sqrt21 or -9+3sqrt21
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Answer:

Option 4: x^2+y^2 = 52

Step-by-step explanation:

Given

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So,

r = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}\\r= \sqrt{(-4-0)^2+(-6-0)^2} \\r = \sqrt{(-4)^2+(-6)^2}\\r = \sqrt{16+36} \\r = \sqrt{52}

As the center is at origin the standard equation will be:

x^2+y^2 = r^2\\

Putting the value of r

x^2+y^2 = (\sqrt{52})^2\\x^2+y^2 = 52

Hence, last option i.e. Option 4 is correct ..

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