From the given information, we have to determine the length of the BC, which is depicted a $x$ , because for the room to be a square, the length of the wall AB must be equal to the length of the wall BC.

In order to determine the length of the wall BC, or $x$ , we will have to employ the Pythagoras' Theorem here. Thus:

$x=\sqrt{(AC)^2-(AB)^2}$

$x=\sqrt{(18.79)^2-(17)^2}\approx\sqrt{64.06} \approx8$

Thus, $BC\approx 8$ inches

$\therefore AB\neq BC$ and hence, the given room is not a square.

8 0

3 years ago

PLEASE HELP!!!! IN NEED OF IT

prisoha [69]

Answer:

Below in bold.

Step-by-step explanation:

This is a regular polygon so all sides are congruent, therefore:

The perimeter of the polygon = 6*34 = 204 units.

We can divide the polygon into 6 conguent triangle with height 30 and base 34.

So area of 1 triangle = 1/2*34*30 = 510.

So area of the polygon = 6 * 510 = 3060 unit^2.

Perimeter of the polygon = 6*34 = 204 units.

6 0

2 years ago