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Novay_Z [31]
2 years ago
6

Pa help po sana plsss

Mathematics
1 answer:
Anna71 [15]2 years ago
8 0

Answer:

Check the attachment.

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Jenny used plastic cone shaped cups to serve punch. The cups were 6 inches in diameter and inches tall. What was the volume of e
Volgvan

Answer:

47.14 in³

Step-by-step explanation:

Here is the complete question

Jenny used plastic cone shaped cups to serve punch. The cups were 6 inches in diameter and 5 inches tall. What was the volume of each cup?

Volume of a cone = \frac{1}{3}πr²h

π = 22/7

Radius = diameter / 2 = 6 /2 = 3 inches

(1/3) x (3^2) x (22/7) x 5  = 47.14 in³

5 0
3 years ago
Plz answe it is worth 10 points thx
vova2212 [387]

Answer:

C

Step-by-step explanation:

4 0
3 years ago
Which polyhedron has more faces than a hexahedron, but fewer faces than an dodecahedron?
timurjin [86]
The best and most correct answer among the choices provided by your question is the fourth choice or letter D.

Octahedron (8) is a <span>polyhedron has more faces than a hexahedron, but fewer faces than an dodecahedron.</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
5 0
3 years ago
Read 2 more answers
The identification code on a bank card consists of 1 digit followed by 2 letters. The code must meet the following conditions: T
jasenka [17]

Answer:

For the code we have 3 selections.

The first selection is a digit that must be odd, so the options are {1, 3, 5, 7 ,9}

So we have 5 options.

The second selection is a letter from the set of all the letters (27) minus the set of the vowels (5)

So here we have 27 - 5 = 22 options

The third selection is also a letter from the previous set, but because each letter can be used only one time, and in the previous selection we already selected one of the letters, in this selection we have a letter less than in the previous selection.

Here we have 22 - 1 = 21 options.

The total number of combinations (of possible codes) is equal to the product of the number of options for each selection:

C = 5*22*21 = 2310.

There are 2310 different possible codes

8 0
3 years ago
Please help. will give brainliest
Temka [501]

Answer:

84 sqmm

Step-by-step explanation:

hope it helps. ........።..

8 0
3 years ago
Read 2 more answers
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