Find the axis of symmetry for this parabola y=-4x^2-8x-6 in an equation

1 answer:

8 0

Y = ax² + bx + c is the equation of a parabola:
y = 4x² -8x -6 is our equation.
The axis of symmetry in a parabola is x = -b/2a
x = -(-8)/(2.4) = - 8/8 and x = - 1 (axis of symmetry

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