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JulsSmile [24]
3 years ago
6

Find the axis of symmetry for this parabola y=-4x^2-8x-6 in an equation

Mathematics
1 answer:
djyliett [7]3 years ago
8 0
Y = ax² + bx + c is the equation of a parabola:
 y = 4x² -8x -6 is our equation.
The axis of symmetry in a parabola is x = -b/2a 
 x = -(-8)/(2.4) = - 8/8 and x = - 1 (axis of symmetry
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1) (-3,-2)

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Step-by-step explanation:

1) The vertex of a parabola is the turning point that is the minimum or maximum of the graph, based on the shape of the parabola. In this case, the vertex is the minimum. By looking at the coordinate points, we can tell that the minimum value where the graph changes the direction is at (-3,-2).

2) The line of symmetry is the line on the graph that cuts the shape exactly in half. This means that if you were to fold the graph along this line, the two sides would be identical. All parabolas have a line of symmetry and it always matches the vertex. The equation for the line of symmetry will be x= whatever the x-value of the vertex is. So, for this graph, the line of symmetry is x=-3.

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Please provide the working outs as well as the answer. Many thanks
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\dfrac{3w-5}{2}=w-3\ \ \ |multiply\ both\ sides\ by\ 2\\\\\not2^1\cdot\dfrac{3w-5}{\not2_1}=2\cdot w-2\cdot3\\\\3w-5=2w-6\ \ \ |add\ 5\ to\ both\ sides\\\\3w-5+5=2w-6+5\\\\3w=2w-1\ \ \ \ |subtract\ 2w\ from\ both\ sides\\\\3w-2w=2w-2w-1\\\\\boxed{w=-1}

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