Answer:
Using the quadratic formula to solve 5x = 6x^2 – 3, what are the values of x?
5x = 6x^2 – 3
Subtract 5x from both sides:
0 = 6x^2 – 5x – 3
a = 6, b = -5, c = -3
x = (-b ± √(b^2 - 4ac))/(2a)
x = (-(-5) ± √((-5)^2 - 4(6)(-3)))/(2(6))
x = (5 ± √(25 + 72))/12
x = (5 ± √(97))/12
Step-by-step explanation:
Start with the point-slope form: 
.
Then you substitue in the slope and coordinates from the point:
You don't do a lot of clean up to the form, with the exception of turning "minus negative 7" into "plus 7".
Thar be yer answer!
Answer:
$12.79
Step-by-step explanation:
$45 - $18.63 = $26.37
$26.37 - ($.47 x 2) = $26.37 - $.94 = $25.43
$25.43 - $12.64 = $12.79
Answer:
<h2>49</h2>
Step-by-step explanation:
Use PEMDAS:
P Parentheses first
E Exponents (ie Powers and Square Roots, etc.)
MD Multiplication and Division (left-to-right)
AS Addition and Subtraction (left-to-right)
==============================================
(-5)² - 2 × (-9) + 6 <em>first </em><em>E</em><em>xponents</em>
25 - 2 × (-9) + 6 <em>next </em><em>M</em><em>ultiplication</em>
25 + 18 + 6 <em>next </em><em>A</em><em>ddition</em>
43 + 6 = 49
It would be: - 2 - (-10) = 5x - 12
= -2 + 10 = 5x - 12
= 8 + 12 = 5x
= x = 20 / 5
= x = 4
