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2 years ago

Use the fact that sin 38 ≈ 0.6157 to solve m.

Mathematics

2 answers:

Elza [17]2 years ago

7 0

Answer:

52°

Step-by-step explanation:

We know that sine and cosine are equal when angles are complementary.

sin 38° = cos m
sin 38° = cos (90° - 38°) = cos 52°
cos m = cos 52°
m = 52°

Anni [7]2 years ago

6 0

Use cos^-1(0.6157) and u might find the answer

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3 years ago

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3 years ago

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Oranges were on sale for $0.45 per pound. Leo bought 12.6 pounds. Which expression shows how to determine the total cost of the

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Answer:

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Step-by-step explanation:

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2 years ago

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Kala, Deandre, and Eric have a total of $119 in their wallets, Kala has $6 more than Deandre. Eric has 3 times what kala has. Ho

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4 0

2 years ago

The average daily temperature, t, in degrees fahrenheit for a city as a function of the month of the year, m, can be modeled by

Vikentia [17]

The answer will be t = $sin((m.\frac{\pi}{6})+55)$ average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

<h3>What is temperature?</h3>

Temperature is the degree or intensity of heat present in a substance or object, especially as expressed according to a comparative scale and shown by a thermometer or perceived by touch.

<h3>TO SOLVE:</h3>

$35cos(\frac{\pi}{6(m+3)}+55)\\\\35 cos(\frac{\pi m}{6} + 55 + \frac{\pi}{2})\\$

suppose $x = m.\frac{\pi}{6}+55$ and $\frac{\pi}{2} = 90$ degree

We know, cos(x+90°) = - sin(X)

⇒ $cos((m.\frac{\pi}{6})+55+90degree)$ degree = - $sin((m.\frac{\pi}{6})+55)$

⇒ t = $sin((m.\frac{\pi}{6})+55)$

Hence the answer will be t = $sin((m.\frac{\pi}{6})+55)$ average daily temperature, t, in degrees Fahrenheit for a city as a function of the month of the year.

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3 0

1 year ago