the answer is i belive 462/3600 because the total amount of times a ribbon has been pulled is 60 and the total amount of times a coin was flipped was 60 times as well so you would do 21/60 times 22/60 which 462/3600Step-by-step explanation:
Answer:
B) {-8,-2,3,4,7,11}
Step-by-step explanation:
range is y
Tan 40 = h / 20 where h = height of the pole.
h = 20 tan 40 = 16.78 feet
Answer:
Maximum area possible
f(max) = 3906,25 ft²
Dimensions:
a = 62,5 ft
w = 62,5 ft
Step-by-step explanation:
Perimeter of the rectangular fencing P = 250 feet
And sides of the rectangle a and w (width of rectangle)
Then
A = a*w
2a + 2w = 250 ⇒ a = (250 -2w)/ 2 ⇒ a = 125 - w
f(w) = (125 - w ) *w f(w) = 125w - w²
Taking derivatives both sides of the equation
f´(w) = 125 - 2w f´(w) = 0 125 - 2w = 0
w = 125/2
w = 62,5 ft ⇒ a = 125 - 62,5
a = 62,5 ft
f(max) = ( 62,5)²
f(max) = 3906,25 ft²
Answer:
Step-by-step explanation:
Since given the expression, this represents graphically a parabola with arms pointing up, and a vertical translation of its vertex 5 units up, then the range of the function must be all the y values such that they are greater or equal to 5. This is written as:
