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const2013 [10]
3 years ago
9

Find the surface area of the right triangular prism (above) using its net (below). units

Mathematics
1 answer:
8_murik_8 [283]3 years ago
6 0

Answer:

120 units^2

Step-by-step explanation:

(12)(5)(0.5)(2) + (12)(2) + (13)(2) + (5)(2) = 120 units^2

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8. The scatter plot shows a hiker's elevation above
g100num [7]

Answer:

The hiker's elevation  after 145 minutes will be 1958 meters.

Step-by-step explanation:

The equation of the trend line of the scatter plot showing a hiker's elevation is y = 8.77x + 686 .......... (1), where x is in minutes (say) and y is in meters (say).

Now, we have to predict the hiker's elevation after 145 minutes.

So, from equation (1) we get, y = 8.77 × 145 + 686 = 1957.65 ≈ 1958 meters. (Answer)

3 0
3 years ago
PLEASE ANSWER ASAP
ss7ja [257]

Answer:

Approximately 0.51

Step-by-step explanation:

3 0
2 years ago
What is the graph of the function y = |x| + 2? How is this graph different from the parent function?
Molodets [167]

Answer:

1

Step-by-step explanation:

5 0
3 years ago
Original Price Of A Sled: $99.50
likoan [24]
49.75

50%=.50
99.50 x .50 = 49.75
3 0
3 years ago
Read 2 more answers
During the first stages of an epidemic, the number of sick people increases exponentially with time. Suppose that at = 0 days th
nydimaria [60]
T = days passed

r = rate of growth

by 0 day, or t = 0, there are 2 folks sick,

\bf \qquad \textit{Amount for Exponential Growth}
\\\\
A=P(1 + r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &2\\
P=\textit{initial amount}\\
r=rate\to r\%\to \frac{r}{100}\\
t=\textit{elapsed time}\to &0\\
\end{cases}
\\\\\\
2=P(1+r)^0\implies 2=P\cdot 1\implies 2=P\qquad \boxed{A=2(1+r)^t}

 by the third day, t = 3, there are 40 folks sick,

\bf \qquad \textit{Amount for Exponential Growth}
\\\\
A=P(1 + r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &40\\
P=\textit{initial amount}\to &2\\
r=rate\to r\%\to \frac{r}{100}\\
t=\textit{elapsed time}\to &3\\
\end{cases}
\\\\\\
40=2(1+r)^3\implies 20=(1+r)^3\implies \sqrt[3]{20}=1+r
\\\\\\
\sqrt[3]{20}-1=r\implies 1.7\approx r\qquad \boxed{A=2(2.7)^t}

how many folks are there sick by t = 6?   \bf \stackrel{that~many}{A=2(2.7)^6}
8 0
3 years ago
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