2 years ago

Бx +7y = -12 5х – 8y = –10

Mathematics

1 answer:

Lesechka [4]2 years ago

4 0

Answer: 32

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

Simplify completely sqrt of 20Y^8

brilliants [131]

Answer:

Final answer is $2y^4 \sqrt{5}$ .

Step-by-step explanation:

Given expression is $\sqrt{20y^8}$ .

Now we need to smplify the given expression $\sqrt{20y^8}$ .

So begin with factoring 20 into two parts so that one part is perfect square number.

$\sqrt{20y^8}$

$=\sqrt{4 \times 5y^8}$

$=\sqrt{4 y^8} \times \sqrt{5}$

$=2y^4 \times \sqrt{5}$

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2 years ago

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EastWind [94]

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Step-by-step explanation:

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