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lutik1710 [3]
3 years ago
12

In the expression 6x^2 + 9, which is the coefficient?

Mathematics
1 answer:
Paha777 [63]3 years ago
5 0

Answer: 6

Step-by-step explanation:

A coefficient is the numerical term that has a constant and variables

In this case it would be 6, as it contains x as the variable

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krok68 [10]

Answer:

3

Step-by-step explanation:

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3 years ago
What is the inverse of the function f(x) = 2x + 1?
aliina [53]
First, conceptually understand what an inverse function is, it makes solving it very intuitive.  An inverse function is simply a function which has points (y,x) for every point (x,y) of the parent function.  So you are essentially taking all points of the parent function and switching the x and y coordinates for each.  Those switched coordinates are produced by the "inverse function".

Mathematically then, finding the inverse function is a matter of solving for x and then switching the variable labels.  In this case:

y=2x+1  subtract 1 from both sides

y-1=2x  divide both sides by 2

(y-1)/2=x  now just switch the labels for the variables...

y=(x-1)/2  so

f^-1(x)=(x-1)/2  is the inverse of f(x)=2x+1
5 0
3 years ago
Help me please ! Thank you
andreev551 [17]
D I think that’s the answer as dark chocolate takes longer to melt then white
4 0
3 years ago
Read 2 more answers
Solve using the box method
Lena [83]

\huge\text{Hey there!}

\large\text{Just SIMPLIFY the given EQUATION or find the DIFFERENCE}\\\large\text{OF the SQUARES... Here is the formula: }\mathsf{\bf a^2 - b^2 =(a+b)(a-b)}

\large\text{Equation: }\mathsf{\dfrac{(4x^2-9)}{(2x + 3)}}

\large\text{Rewrite }\mathsf{ 4x^9 - 9}\large\text{ in the formation of }\mathsf{a^2 - b^2}\large\text{ whereas}\mathsf{a = 2x \ \&\ b = 3.}

\large\text{Equation: }\mathsf{\dfrac{(2x)^2-3^2}{2x + 3}}

\large\text{This is where you try to do the DIFFERENCE OF its SQUARES}

\mathsf{\dfrac{(2x + 3)(2x - 3)}{2x + 3}}

\large\text{CANCEL out: }\mathsf{(2x + 3)\ - (2x +3)}\large\text{ because it gives you 0}

\large\text{This leaves us with }\mathsf{\bf 2x - 3}\large\text{ as your POSSIBLE  ANSWER}

\boxed{\boxed{\large\text{Answer: \huge \bf 2x - 3}}}\huge\checkmark

\text{Good luck on your assignment and enjoy your day!}

~\frak{Amphitrite1040:)}

\large\text{Note: There is/are many ways to solve for equations like this.... this was just}\\\large\text{the quickest and easiest way to understand it!}

3 0
3 years ago
Simplify 2x^3y^-3•2x^-1y^3
algol [13]
I hope this helps you

3 0
3 years ago
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