The Vanderbilt University Institute for Imaging Science (VUIIS) Center for Computational Imaging (CCI) is known to have made a database built on XNAT housing that is said to house about a quarter of a million scans.
<h3>What is the institute about?</h3>
The above study was said go have used the database that gave a framework for:
- Fast prototyping
- large volume batch processing of images
- Scalable project management.
The above system is one that make use of the web-based interfaces of XNAT and REDCap to give room for graphical interaction.
Hence, the Distributed Automation for XNAT (DAX) package, is one that shares computation in all of Vanderbilt Advanced Computing Center for Research and Education high form of computing center.
Therefore, The Vanderbilt University Institute for Imaging Science (VUIIS) Center for Computational Imaging (CCI) is known to have made a database built on XNAT housing that is said to house about a quarter of a million scans.
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It is a matter of opinion but I prefer chocolate
The reason why iron oxide has more mass than the iron is because Iron oxide has oxygen atoms, and pure iron does not.
When iron rusts and forms iron oxide, the iron oxide has more mass than the iron. Which statement correctly explains this
observation?
(A)Iron oxide has oxygen atoms, and pure iron does not.
(B)The oxygen atoms in iron oxide have more mass than the iron atoms in pure iron.
(C)The iron atoms in iron oxide have more mass than pure iron.
(D)There are more iron atoms in iron oxide than in pure iron.
When a chemical reaction takes place, other atoms are combined with pure elements to form compounds. This addition of another atom (oxygen) after reaction makes iron oxide formed heavier than pure iron.
Iron oxide is a chemical substance formed when pure iron rusts. The formation of iron oxide is a chemical reaction.
Hence, the correct answer to the question is; the iron is heavier because Iron oxide has oxygen atoms, and pure iron does not.
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Answer:
29 %
Explanation:
check the table for given condition and divide by total no of students
