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kvasek [131]
2 years ago
10

What is the solution to the system of equations? (Hint: Use Substitution.)

Mathematics
1 answer:
Jet001 [13]2 years ago
8 0

Answer:

(-1,9)

Step-by-step explanation:

y = -3x + 6

y = 9

-3x + 6 = 9

-3x = 3

x = -1

y is already given as 9, but you can solve for y by plugging the x value into y = -3x + 6,

-3(-1) + 6 = 9

(-1,9)

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Answer:

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Step-by-step explanation:

The given expression is

\sqrt[3]{216x^9y^{18}}

It can be written as

Use the exponent property: a^{mn}=(a^m)^n

\sqrt[3]{216x^9y^{18}}=\sqrt[3]{6^3(x^3)^3(y^6)^{3}}

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\sqrt[3]{216x^9y^{18}}=6x^3y^6

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