Question

Can anyone help me to solve the question

Answer 1

Answer:

I think the image above will help you.

Answer 2

Answer:

x = 2$\sqrt{10}$

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides , that is

x² + 9² = 11²

x² + 81 = 121 ( subtract 81 from both sides )

x² = 40 ( take square root of both sides )

x = $\sqrt{40}$ = $\sqrt{4(10)}$ = $\sqrt{4}$ × $\sqrt{10}$ = 2$\sqrt{10}$ ≈ 6.32 ( to 2 dec. places )