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Radda [10]
2 years ago
8

Which equation would best help solve the following problem?

Mathematics
2 answers:
Elina [12.6K]2 years ago
8 0

Let the base be x and height be x-5 and area is given i.e. 42m²

According to the formula of area:

\boxed{ \sf \: area =  \frac{1}{2}  \times base \times height}

<h3>So,</h3>

\tt \: 42 =  \frac{1}{2}  \times (x) \times (x - 5)

<em>Thus, Option B is the correct choice!!~</em>

Dominik [7]2 years ago
7 0

Answer:

B

Step-by-step explanation:

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Which attribute matches the given triangle? Column A Column B 1. isosceles triangle 2. obtuse triangle 3. equilateral triangle 4
polet [3.4K]
Isosceles - Has at least two equal sides. (B)
Obtuse Triangle - Must have an obtuse angle. (D)
Equilateral Triangle - All sides should be equal. (Missing an answer?)
Right Triangle -Must include a 90 degree angle. (A)
Scalene Triangle - Has NO equal sides. (C)

Tell me if this helped.
6 0
4 years ago
je Jessie competes in a hot dog eating contest he can eat in 8 minutes how many can he eat in 12 minutes
WITCHER [35]
He can eat about 3-4 hot dogs
5 0
3 years ago
Read 2 more answers
Graph these equations: x+2y=6, y=-1/2x+4 How many solutions does the system of equations have?
inysia [295]

Answer:

The system has no solution

Step-by-step explanation:

we have

x+2y=6

Isolate the variable y

2y=-x+6

Divide by 2 both sides

y=-\frac{x}{2}+3 ---> equation A

y=-\frac{x}{2}+4 ---> equation B

Compare the equations

Equation A and equation B have the same slope and different y-intercept

Remember that

If two lines have the same slope, then the lines are parallel

The solution of the system is the intersection point both graphs

In this problem, the lines don't intersect, therefore, the system has no solution

using a graphing tool

The graph in the attached figure

7 0
3 years ago
What is the product of 4.5 × 10-5 and 2.4 × 10-2?
nikitadnepr [17]
4.5 • 10-5 = 40

2.4 • 10-2 = 22
4 0
3 years ago
Read 2 more answers
A skier has decided that on each trip down a slope, she will do 3 more jumps than before. On her first trip she did 5 jumps. Der
taurus [48]
Since we are already given the amount of jumps from the first trial, and how much it should be increased by on each succeeding trial, we can already solve for the amount of jumps from the first through tenth trials. Starting from 5 and adding 3 each time, we get: 5 8 (11) 14 17 20 23 26 29 32, with 11 being the third trial.

Having been provided 2 different sigma notations, which I assume are choices to the question, we can substitute the initial value to see if it does match the result of the 3rd trial which we obtained by manual adding.

Let us try it below:

Sigma notation 1:

  10
<span>   Σ (2i + 3)
</span>i = 3

@ i = 3

2(3) + 3
12

The first sigma notation does not have the same result, so we move on to the next.

  10
<span>   Σ (3i + 2)
</span><span>i = 3
</span>
When i = 3; <span>3(3) + 2 = 11. (OK)
</span>
Since the 3rd trial is a match, we test it with the other values for the 4th through 10th trials.

When i = 4; <span>3(4) + 2 = 14. (OK)
</span>When i = 5; <span>3(5) + 2 = 17. (OK)
</span>When i = 6; <span>3(6) + 2 = 20. (OK)
</span>When i = 7; 3(7) + 2 = 23. (OK)
When i = 8; <span>3(8) + 2 = 26. (OK)
</span>When i = 9; <span>3(9) + 2 = 29. (OK)
</span>When i = 10; <span>3(10) + 2 = 32. (OK)

Adding the results from her 3rd through 10th trials: </span><span>11 + 14 + 17 + 20 + 23 + 26 + 29 + 32 = 172.
</span>
Therefore, the total jumps she had made from her third to tenth trips is 172.


3 0
3 years ago
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