Answer:
a. ∆EGF ≅ ∆EGD
Step-by-step explanation:
Congruent triangles would have the same side lengths and the same measure of angles.
From the figure given:
EG in ∆EGF ≅ EG in ∆EGD
GF in ∆EGF ≅ GD in ∆EGD, also
EF ≅ ED.
The three angles in ∆EFG are also congruent to the three angles in ∆EGD.
Therefore, ∆EGD is congruent to ∆EGF.
∆EGF ≅ ∆EGD
Answer:
a = length of the base = 2.172 m
b = width of the base = 1.357 m
c = height = 4.072 m
Step-by-step explanation:
Suppose we want to build a rectangular storage container with open top whose volume is 12 cubic meters. Assume that the cost of materials for the base is 12 dollars per square meter, and the cost of materials for the sides is 8 dollars per square meter. The height of the box is three times the width of the base. What’s the least amount of money we can spend to build such a container?
lets call a = length of the base
b = width of the base
c = height
V = a.b.c = 12
Area without the top:
Area = ab + 2bc + 2ac
Cost = 12ab + 8.2bc + 8.2ac
Cost = 12ab + 16bc + 16ac
height = 3.width
c = 3b
Cost = 12ab + 16b.3b + 16a.3b = 12ab + 48b² + 48ab = 48b² + 60ab
abc = 12 → ab.3b = 12 → 3ab² = 12 → ab² = 4 → a = 4/b²
Cost = 48b² + 60ab = 48b² + 60b.4/b² = 48b² + 240/b
C(b) = 48b² + 240/b
C'(b) = 96b - 240/b²
Minimum cost: C'(b) = 0
96b - 240/b² = 0
(96b³ - 240)/b² = 0
96b³ - 240 = 0
96b³ = 240
b³ = 240/96
b³ = 2.5
b = 1.357m
c = 3b = 3*1.357 = 4.072m
a = 4/b² = 2.172m
Answer:
<em>Center: (3,3)</em>
<em>Radius: </em>
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Step-by-step explanation:
<u>Midpoint and Distance Between two Points</u>
Given two points A(x1,y1) and B(x2,y2), the midpoint M(xm,ym) between A and B has the following coordinates:


The distance between both points is given by:

Point (5,7) is the center of circle A, and point (1,-1) is the center of the circle B. Given both points belong to circle C, the center of C must be the midpoint from A to B:


Center of circle C: (3,3)
The radius of C is half the distance between A and B:


The radius of C is d/2:

Center: (3,3)
Radius: 
Answer:
The height of near by tree will be 90 feet.
Step-by-step explanation:
Considering the water triangle as shown in figure a.
As the old faithful shoots water 60 feet into the air that casts a shadow of 42 feet.
Considering the tree triangle as shown in figure a. The tree triangle has a shadow 63 feet long.
Let x be the height of near by tree that cost a shadow 63 feet long.
Assuming that the triangles are similar
So,
the ratios of similar triangles will be related as:




feet
Therefore, the height of near by tree will be 90 feet.
Keywords: ratio, similar triangle
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Answer:
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Step-by-step explanation:
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