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AysviL [449]
2 years ago
11

BD bisects ABC. Find the value of x.

Mathematics
1 answer:
yuradex [85]2 years ago
6 0
90-52=38

38=3x-5

3x=43

x=14.3
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+
dmitriy555 [2]

Answer:

+ + + + += + + + + +

Step-by-step explanation:

DUH        

I mean I think I'm right

8 0
3 years ago
Find the missing side of each triangle. i need help!!!
Nezavi [6.7K]

Answer:

√161 yd

Step-by-step explanation:

Hi there!

We're given a right triangle (notice the right angle), the measure of one of the legs (one of the sides that make up the right angle) as 8 yd, and the hypotenuse (the side opposite to the right angle) as 15 yd.

We need to find x, which is the other leg in the triangle

If we are given 2 sides and need to find a third, we can use Pythagorean Theorem, which states that a²+b²=c² if a and b are legs and c is the hypotenuse

In this case, a=8, b=x, and c=15

So let's substitute those values into the formula

(8)²+x²=(15)²

raise everything to the second power

64+x²=225

subtract 64 from both sides

x²=161

take the square root of both x and 161

x=√161, x=-√161

-√161 cannot work in this case, as distance cannot be negative.

The question asks for the answer to be in simplified radical form, but √161 cannot be simplified down further

so the answer is <u>√161 yd</u>

Hope this helps! :)

3 0
3 years ago
Can someone make sure the first 3 questions are correct and help me on the 4th one?
Ratling [72]
Sorry, I'm no help because I have no idea how to do those!
4 0
3 years ago
Help<br> help please please
Ahat [919]

Answer:

1. A

2. C

Step-by-step explanation:

I could be wrong, that's my best guess. Im so sorry if im wrong, have a good day

7 0
3 years ago
Write the equation in standard form for the circle with center (0, – 10) and radius 6.
Artemon [7]

Answer:

Equation of circle in standard form with centre (0, – 10) and radius 6. \mathbf{x^2+(y+10)^2=36}

Step-by-step explanation:

We need to write equation of circle in standard form with centre (0, – 10) and radius 6.

The equation of circle is: (x-h)^2+(y-k)^2=r^2

where (h,k) is centre of circle and r is radius

We are given centre (0,-10) so, h=0, k=-10 and radius r = 6

Putting values and finding equation:

(x-h)^2+(y-k)^2=r^2\\(x-0)^2+(y-(-10))^2=(6)^2\\x^2+(y+10)^2=36

So, equation of circle in standard form with centre (0, – 10) and radius 6. \mathbf{x^2+(y+10)^2=36}

5 0
3 years ago
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