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AlladinOne [14]
2 years ago
9

503497and 26475 The value of 7 in_ is- times the value of 7 in-

Mathematics
2 answers:
Ksenya-84 [330]2 years ago
7 0

In comparison 503497 and 26475,

The value of 7 in 26475 is ten times the value of 7 in 503497

7 x 10 = 70

hope this helps

kipiarov [429]2 years ago
7 0

The value of 7 in 26475 is ten times the value of the value of 7 in 503497.

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If <img src="https://tex.z-dn.net/?f=%20x%20%3D%20%5Cfrac%7B2y%7D%7Ba%7D%20" id="TexFormula1" title=" x = \frac{2y}{a} " alt=" x
inessss [21]

\bf A) \\\\\\ \cfrac{3\left( \frac{2y}{a} \right)}{y}\implies \cfrac{\frac{6y}{a}}{y}\implies \cfrac{6y}{a}\cdot \cfrac{1}{y}\implies \cfrac{6}{a}\quad \otimes \\\\\\ B) \\\\\\ \cfrac{6\left( \frac{2y}{a} \right)}{y}\implies\cfrac{\frac{12y}{a}}{y}\implies \cfrac{12y}{a}\cdot \cfrac{1}{y}\implies \cfrac{12}{a}\quad \otimes \\\\\\ C) \\\\\\ \cfrac{6y}{\left( \frac{2y}{a} \right)}\implies \cfrac{6y}{1}\cdot \cfrac{a}{2y}\implies 3a\quad \otimes

\bf D) \\\\\\ \cfrac{12\left( \frac{2y}{a} \right)}{y}\implies \cfrac{\frac{24y}{a}}{y}\implies \cfrac{24y}{a}\cdot \cfrac{1}{y}\implies \cfrac{24}{a}\quad \otimes \\\\\\ E) \\\\\\ \cfrac{12y}{\left( \frac{2y}{a} \right)}\implies \cfrac{12y}{1}\cdot \cfrac{a}{2y}\implies 6a\quad \checkmark

4 0
3 years ago
What is the input value for which g(x) = -2?<br><br><br> x = ?
Zina [86]

g(x)=-2

Simplfy: y=-2

x=-9

*Look at where the points intersect

3 0
3 years ago
Beth is putting liquid fertilizer on the plants in 4 flowerpots. her measuring spoon holds 1/8 teaspoon the directions say to pu
VARVARA [1.3K]
20 times 1/8+1/8+1/8+1/8+1/8=5/8 times 4 because of the four pots = 20
5 0
3 years ago
Read 2 more answers
A group of 570 students were surveyed about the courses they were taking at their college with the following results:
garri49 [273]

Answer:

The number of students who took English and History, but not Math is 143.

Step-by-step explanation:

Denote the subject choices as follows:

<em>M</em> = a students was taking Math

<em>E</em> = a students was taking English

<em>H</em> = a students was taking History

The data provided is as follows:

N (M) = 257

N (E) = 282

N (H) = 323

n (M ∩ E) = 154

n (M ∩ H) = 171

n (E ∩ H) = 143

n (M ∩ E ∩ H) = 80

Consider the Venn diagram below.

From the provided data and the Venn diagram the value of the set E and H minus M is 143.

Thus, the number of students who took English and History, but not Math is 143.

7 0
2 years ago
35 Points!!
nexus9112 [7]

Answer:

- Equal midpoints of AC and BC.

- The product of the slopes of the diagonals AC and DB is -1.

Step-by-step explanation:

1. Plot the given points, as you can see in the graph attached.

2. Calculate the midpoint of AC and DB:

M_{AC}=(\frac{-5+(-1)}{2},\frac{-1+5}{2})=(-3,2)\\M_{DB}=(\frac{-9+3}{2},\frac{6+(-2)}{2})=(-3,2)

Therefore, the midpoint of AC and DB are equal.

3. Calculte the slope of the diagonals AC and DB:

m_{AC}=\frac{5-(-1)}{-1-(-5)}=\frac{3}{2}\\m_{DB}=\frac{-2-6)}{3-(-9)}=-\frac{2}{3}

4. Multiply the slopes of the diagonals:

(\frac{3}{2})(-\frac{2}{3})=-1 (AC and DB are perpendicular)

5 0
3 years ago
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