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Yuki888 [10]
2 years ago
14

Can someone step by step explain the answer to me please and thank u

Mathematics
1 answer:
True [87]2 years ago
3 0

First

angle in front of c is 30°, so hypotenuse is equal to 2c

it's right triangle, so let's use Pythagorean theorem\

(2c)^2=c^2+4^2\\4c^2=c^2+16\\3c^2=16\\\\c^2=\dfrac{16}{3} \\\\c=\dfrac{4}{\sqrt{3} } =\dfrac{4\sqrt{3} }{3 }

Second

b - the base of the triangle, angles at the base are equal ⇒ cathets are equal

it's right triangle, so let's use Pythagorean theorem

b^2=7^2+7^2\\b^2=49+49\\b=\sqrt{2\times49} =7\sqrt{2}

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Rewrite the radical expression as an expression with rational exponents.
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Answer:

x^(7/5)

Step-by-step explanation:

Root goes on bottom of fraction

Power goes on top

x^(7/5)

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Step-by-step explanation:

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3 years ago
Math problem plz help​
Firlakuza [10]

Answer:

5/2 x 1/2

Step-by-step explanation:

when you multiply fractions you multiply trait across meaning you do 5*1 and 2*2 which leaves you with 5/4 and that is equivalent to 1 &1/4

5 0
3 years ago
Calculate two iterations of Newton's Method for the function using the given initial guess. (Round your answers to four decimal
pickupchik [31]

Answer:

The first and second iteration of Newton's Method are 3 and \frac{11}{6}.

Step-by-step explanation:

The Newton's Method is a multi-step numerical method for continuous diffentiable function of the form f(x) = 0 based on the following formula:

x_{i+1} = x_{i} -\frac{f(x_{i})}{f'(x_{i})}

Where:

x_{i} - i-th Approximation, dimensionless.

x_{i+1} - (i+1)-th Approximation, dimensionless.

f(x_{i}) - Function evaluated at i-th Approximation, dimensionless.

f'(x_{i}) - First derivative evaluated at (i+1)-th Approximation, dimensionless.

Let be f(x) = x^{2}-8 and f'(x) = 2\cdot x, the resultant expression is:

x_{i+1} = x_{i} -\frac{x_{i}^{2}-8}{2\cdot x_{i}}

First iteration: (x_{1} = 2)

x_{2} = 2-\frac{2^{2}-8}{2\cdot (2)}

x_{2} = 2 + \frac{4}{4}

x_{2} = 3

Second iteration: (x_{2} = 3)

x_{3} = 3-\frac{3^{2}-8}{2\cdot (3)}

x_{3} = 2 - \frac{1}{6}

x_{3} = \frac{11}{6}

7 0
4 years ago
If f(x) = 7x^2 - 3x +1 and g(x) = 3x - 2, find the following by matching.
Cloud [144]

f(x) = 7x² - 3x + 1

g(x) = 3x - 2


1. g(0) This means that x is 0, so you can plug in 0 for x in the equation:

g(x) = 3x - 2

g(0) = 3(0) - 2

g(0) = -2


2. g(1)    x is 1

g(x) = 3x - 2

g(1) = 3(1) - 2

g(1) = 3 - 2

g(1) = 1


3. f(1)     x is 1

f(x) = 7x²- 3x + 1

f(1) = 7(1)² - 3(1) + 1

f(1) = 7 - 3 + 1

f(1) = 5


4. f(x) = 7x²- 3x + 1

f(-2) = 7(-2)²- 3(-2) + 1

f(-2) = 7(4) + 6 + 1

f(-2) = 28 + 7

f(-2) = 35

4 0
3 years ago
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