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inn [45]
2 years ago
5

The product $ab = 1200$, $a$ is an integer, and $b$ is an odd integer. What is the largest possible value of $b$?.

Mathematics
1 answer:
lana66690 [7]2 years ago
7 0
<h3>ANSWER:</h3>

Largest possible value of b is:

75

<h3>Step-by-step explanation:</h3>

we are given that:

ab=1200

where a is an integer and b is an odd integer.

we know that product of odd numbers is always odd.

Now, 1200= 12×100

               = 2×6×10×10

              =2×2×3×2×5×2×5

It cannot be factorized further

Now, considering the product of all odd numbers

=3×5×5

=75

Now, if we multiply any other remaining number from the factorization of 1200, we will get a even number

Hence, The largest possible value of b is:

75

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Answer:

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Step-by-step explanation:

a. Given:

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y = y₀ + v₀ t + ½ at²

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h = 60t − 4.9t²

b. When the ball lands, h = 0.

0 = 60t − 4.9t²

0 = t (60 − 4.9t)

t = 0 or 12.2

The ball lands after 12.2 seconds.

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t = -b / (2a)

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t = 6.1 seconds

Alternatively, the maximum height is reached at half the time it takes to land.

t = 12.2 / 2

t = 6.1 seconds

After 6.1 seconds, the height reached is:

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h = 183.7 meters

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3 years ago
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What transformation takes the graph of f(x)=2x+3 to the graph of g(x)=2x+4 ?
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