Answer:
An adult ticket is 17
A childs ticket costs 12 dollars
Step-by-step explanation:
Let a = adult price
c = child price
3a + 4c = 99
2a + 3c = 70
Multiply the first equation by 2
2(3a + 4c) = 99*2
6a + 8c = 198
Multiply the second equation by -3
-3 (2a + 3c) = 70*-3
-6a -9c = -210
Add these new equations together
6a + 8c = 198
-6a -9c = -210
----------------------
-c = -12
Multiply by -1
c = 12
A childs ticket costs 12 dollars
Now we need to find the price of an adult ticket
2a + 3c = 70
2a + 3(12) = 70
2a +36 = 70
Subtract 36 from each side
2a +36-36 =70-36
2a = 34
Divide by 2
2a/2 = 34/2
a = 17
An adult ticket is 17
Answer:
The sample consisting of 64 data values would give a greater precision.
Step-by-step explanation:
The width of a (1 - <em>α</em>)% confidence interval for population mean μ is:

So, from the formula of the width of the interval it is clear that the width is inversely proportion to the sample size (<em>n</em>).
That is, as the sample size increases the interval width would decrease and as the sample size decreases the interval width would increase.
Here it is provided that two different samples will be taken from the same population of test scores and a 95% confidence interval will be constructed for each sample to estimate the population mean.
The two sample sizes are:
<em>n</em>₁ = 25
<em>n</em>₂ = 64
The 95% confidence interval constructed using the sample of 64 values will have a smaller width than the the one constructed using the sample of 25 values.
Width for n = 25:
Width for n = 64:
![\text{Width}=2\cdot z_{\alpha/2}\cdot \frac{\sigma}{\sqrt{64}}=\frac{1}{8}\cdot [2\cdot z_{\alpha/2}\cdot \sigma]](https://tex.z-dn.net/?f=%5Ctext%7BWidth%7D%3D2%5Ccdot%20z_%7B%5Calpha%2F2%7D%5Ccdot%20%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7B64%7D%7D%3D%5Cfrac%7B1%7D%7B8%7D%5Ccdot%20%5B2%5Ccdot%20z_%7B%5Calpha%2F2%7D%5Ccdot%20%5Csigma%5D)
Thus, the sample consisting of 64 data values would give a greater precision
B because 10p means 10 × p
Notice that the two semicircles have a radius of 10/2=5 and that their area is simply the area of a complete circle with a radius of 5. In the center you have a rectangle that is 10 by 8. So the total area is:
A=pr^2+xy
A=25p+80 m^2
A≈158.53 which is:
A≈158.5 m^2 (to the nearest tenth of a m^2)