2000000000 is your answer.
Answer:
the answer is 1/27. C :))
Before we start, let's plot the graph of the hyperbola:
The problem wants the distance across the base of the base, we can see that at y = 0 (base) the "vases" touches x = 2.935. that's the distance between the center of the base and the end of it, looking at the image we can see that basically, it's the distance between the x-intercept, we know that half of the distance is 2.935, then the distance is
![\begin{gathered} \frac{d}{2}=2.935 \\ \\ d=2\cdot2.935 \\ \\ d=5.87\text{ inches} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Cfrac%7Bd%7D%7B2%7D%3D2.935%20%5C%5C%20%20%5C%5C%20d%3D2%5Ccdot2.935%20%5C%5C%20%20%5C%5C%20d%3D5.87%5Ctext%7B%20inches%7D%20%5Cend%7Bgathered%7D)
Therefore, the correct answer is 5.87 inches, distance between x-intercept
Step-by-step explanation:
hhggghj I am very sorry sorry
10% = 10g/100ml. Ergo, 15ml/100ml (10g) = 1500mg of KCL
.9% NACL = 9g/1000mL, Ergo = 9000mg NaCl
Now we have to figure out how many mEqs of each salt we have.
MW of NaCl = 58.5
MW of KCl = 74.5
So, in moles, we have:
1500 KCl / 74.5 = 20.13 mmol KCl
9000 NaCl / 58.5 = 153.85mmol NaCl
Because the valence of both ions is one, as an example, it would be both 20.13 mEq of Cl- and K+ from 20.13 mmoles of KCL.
So, just add the two together, 20.13 + 153.85 = 174-ish.