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Natali [406]
3 years ago
15

Write an even square number smaller than 100.

Mathematics
1 answer:
yulyashka [42]3 years ago
7 0

Answer:

I believe you mean what square number that is less than 100 has the most factors.  

The square numbers under 100 are 1, 4, 9, 16, 25, 36, 49, 64, and 81.  

1 obviously only factors to 1*1.

4, 9, 25, and 49 are square of prime numbers. If we call the original number n and the root p (for prime) each of them can only be factored as 1*n or p*p. example: 1*4, 2*2 .We can eliminate those.  

16 and 81 are not only squares, but the fourth power of a prime (2 and 3) respectively. They can be factored as 1*n, (p^3)*p, or (p^2*p^2). Example: 1*16, 8*2, or 4*4.

But 36 is 2*2*3*3 as it’s prime factoring. This allows us to find more combinations of factors: 1*36, 2*18, 4*9, 12*3, or 6*6.

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Please help if you know trigonometry ;)
seraphim [82]

Answer:

12.73m

Step-by-step explanation:

using Pythagoras theorem

a = x (i change x to a for easy reference due to multiplication)

18 x 18 = a x a + a x a

324 = 2a^2

a^2 = 324 / 2= 162

a = \sqrt{162} = 12.7279 = 12.73 (2 decimal place)

8 0
4 years ago
Read 2 more answers
10. RECREATION In a game of kickball, Rickie has to kick the
wel

Answer:

The angle Rick must kick the ball to score is an angle between the lines BX and BZY which is less than or equal to 32°

Step-by-step explanation:

The given measures of the of the angle formed by the tangent to the given circle at X and the secant passing through the circle at Z and Y are;

m\widehat{XZ}  = 58^{\circ}

m\widehat{XY}  = 122^{\circ}

The direction Rick must kick the ball to score is therefore, between the lines BX and BXY

The angle between the lines BX and BXY = ∠XBZ = ∠XBY

The goal is an angle between m\widehat{XY}

Let 'θ' represent the angle Rick must kick the ball to score

Therefore the angle Rick must kick the ball to score is an angle less than or equal to ∠XBZ = ∠XBY

By the Angle Outside the Circle Theorem, we have;

The angle formed outside the circle = (1/2) × The difference of the arcs intercepted by the tangent and the secant

\therefore \angle XBZ = \dfrac{1}{2} \times \left (m\widehat{XY}  -m\widehat{XZ} \right)

We get;

∠XBZ = (1/2) × (122° - 58°) = 32°

The angle Rick must kick the ball to score, θ = ∠XBZ ≤ 32°

4 0
3 years ago
If h(x) equals negative 7 (x minus 8 ) plus 2 find the value of h (negative 5)
vichka [17]

Answer:

h = -7x - 11

Step-by-step explanation:

6 0
3 years ago
A record album is 3/16 of an inch thick. How many albums can be stacked to fit in a box 12 inches high? Please show me how you g
german
Hope this was helpful

5 0
3 years ago
The following table shows the estimated populations and annual growth rates for four countries in the year 2000. Find the expect
Liula [17]

Answer:

After 25 years the population will be:

  • Australia: 22271200
  • China: 1580220878
  • Mexico: 157380127
  • Zaire: 112794819

Step-by-step explanation:

Growth rate problem that has a growth rate proportional to the population size can be solved using the equation:

 P(t) = P₀eʳᵗ

  • t is your unit of time. It could be days, or hours, or minutes. It changes depending on each problem. In this problem, t is measured in years because you're jumping from 2000 to 2025. Years just makes the most sense to measure that leap in time.
  • P(t) is the population at time t. An example in this problem could be P(20) would be the population 20 years after the initial count. or maybe P(12) would be the population 12 years after the initial count. or P(0) would be the initial count of the population.
  • P₀ is the initial population at P(0)
  • r is the growth rate.<u><em> Don't forget to convert the percentage to its decimal form</em></u>

Now that everything is set out, lets use the equation to solve for our answer.

P(t) = P₀eʳᵗ

<u>Australia:</u>

P(t)=(19169000)e^{(0.006)t}

after 25 years

P(25)=(19169000)e^{(0.006)(25)}=22271200.6

<u>China:</u>

P(t) = (1261832000)e^{(.009)t}

after 25 years:

P(25)=(1261832000)e^{(.009)(25)}=1580220878

<u>Mexico:</u>

P(t) = (100350000)e^{(0.018)t}

after 25 years:

P(25)=(100350000)e^{(0.018)(25)}=157380127.8

<u>Zaire:</u>

P(t) = (51965000)e^{(0.031)t}

after 25 years:

P(25)=(51965000)e^{(0.031)(25)}=112794819.9

6 0
4 years ago
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