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Natali [406]
3 years ago
15

Write an even square number smaller than 100.

Mathematics
1 answer:
yulyashka [42]3 years ago
7 0

Answer:

I believe you mean what square number that is less than 100 has the most factors.  

The square numbers under 100 are 1, 4, 9, 16, 25, 36, 49, 64, and 81.  

1 obviously only factors to 1*1.

4, 9, 25, and 49 are square of prime numbers. If we call the original number n and the root p (for prime) each of them can only be factored as 1*n or p*p. example: 1*4, 2*2 .We can eliminate those.  

16 and 81 are not only squares, but the fourth power of a prime (2 and 3) respectively. They can be factored as 1*n, (p^3)*p, or (p^2*p^2). Example: 1*16, 8*2, or 4*4.

But 36 is 2*2*3*3 as it’s prime factoring. This allows us to find more combinations of factors: 1*36, 2*18, 4*9, 12*3, or 6*6.

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Out of a total of 10 college textbooks estimate the standard deviation of their ages if the oldest textbook is known to be 7.9 y
tamaranim1 [39]

Answer:

Given that the maximum age of the textbook is 7.9 years and the minimum age of the textbook is 1.3 years.

Using the range rule, the standard deviation is estimated as,

S≈maximum−minimum/4

=7.9−1.3/4

=1.65

The required value of the approximate standard deviation is 1.65.

8 0
3 years ago
Please answer this question
Afina-wow [57]

Answer:

The answer is

Step-by-step explanation:

Given: f(x) = 3 + 2x - x²

To compute f(3 + h) substitute x = 3 + h.

Similarly, to compute f(h) simply substitute x = h.

We are asked to compute $ \frac{f(3 + h) - f(h)}{h} $

f(3 + h) = 3 + 2(3 + h) - {(3 + h)²}

           = 3 + 6 + 2h - {9 + 6h + h²}

           = 9 + 2h - 9 - 6h - h²

           = - 4h - h²

Now, f(h) = 3 + 2h - h²

f(3 + h) - f(h) = -4h - h² - 3 - 2h + h²

                    = -6h - 3

$ \therefore \frac{f(3 + h) - f(h)}{h} = \frac{-3(2h + 1)}{h} $ which is the required answer.

6 0
3 years ago
Can someone help me with this please
yuradex [85]
The Answer to this question is negative eight after substituting in the 2 and solving to get to 9, negative 8 solves this problem.
7 0
3 years ago
Find the points having x-coordinate of 9 whose distance from the point (3,-2) is 10.
kotegsom [21]

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{3}~,~\stackrel{y_1}{-2})\qquad (\stackrel{x_2}{9}~,~\stackrel{y_2}{y})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{d}{10}=\sqrt{[9-3]^2+[y-(-2)^2]}\implies 10=\sqrt{(9-3)^2+(y+2)^2} \\\\\\ 10=\sqrt{6^2+\stackrel{FOIL}{(y^2+4y+4)}}\implies 10^2=36+(y^2+4y+4)


\bf 100=y^2+4y+40\implies 0=y^2+4y-60 \\\\\\ 0=(y+10)(y-6)\implies y= \begin{cases} -10\\ 6 \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill (9,-10)\qquad (9,6)~\hfill

3 0
4 years ago
hello could you please help me with this math problem with full explanation which I am unable to solve? Thanks.
neonofarm [45]

Answer:

8 / sqrt(3)

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp / adj

tan A = BC / AC

tan 30 = BC / 8

8 tan 30 = BC

8 * sqrt(3)/3 = BC

8/3 sqrt(3) = BC

7 0
4 years ago
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