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Nady [450]
2 years ago
12

6. Karla keeps a log to determine how many minutes she spends on daily tasks. She makes a table to

Mathematics
1 answer:
IRINA_888 [86]2 years ago
6 0

Answer:

60 seconds greater

Step-by-step explanation:

1 = 60

2 = 120

3 = 180

4 = 240

5 = 300

6 = 360

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HELP MEEEEE EASY DUE IN A MINSS<br> What is the prime factorization of 990?
alex41 [277]

Answer:

11 is one of the factors! The orange divisor(s) above are the prime factors of the number 990. If we put all of it together we have the factors 2 x 3 x 3 x 5 x 11 = 990.

Step-by-step explanation:

3 0
3 years ago
One computer has a mass 0.8 and another has a mass of 800 grams compare the masses of the computer.use &gt; &lt; = to make a tru
Artyom0805 [142]
Since 800 is greater than 0.8 your statement would be 800>0.8
4 0
3 years ago
Why does math even exist?
natita [175]
I know I dislike it as well! Sorry you are having trouble with it! :)
4 0
3 years ago
Read 2 more answers
(64x^8– 4x^3 + 24) : (8x^3)
andrey2020 [161]

Answer:

(16 x^8 - x^3 + 6)/(2 x^3)

Step-by-step explanation:

Simplify the following:

(64 x^8 - 4 x^3 + 24)/(8 x^3)

Factor 4 out of 64 x^8 - 4 x^3 + 24:

(4 (16 x^8 - x^3 + 6))/(8 x^3)

4/8 = 4/(4×2) = 1/2:

Answer: (16 x^8 - x^3 + 6)/(2 x^3)

7 0
3 years ago
Bags of pretzels are sampled to ensure proper weight. The overall average for the samples is 9 ounces. Each sample contains 25 b
77julia77 [94]

Answer:

The value is UCL  =  10.8  

Step-by-step explanation:

From the question we are told that

    The sample mean is  \= x  =  9 \  ounce

    The sample size is  n =  25

    The standard deviation is  \sigma =  3 \ ounce

Given that the sample size is not large enough i.e  n<  30  we will make use of the student t distribution table  

From the question we are told the confidence level is  99.7% , hence the level of significance is    

      \alpha = (100 -99.7 ) \%

=>   \alpha = 0.003

Generally the degree of freedom is  df =  n- 1

=>  df =  25 - 1

=>  df =  24  

Generally from the student t distribution table the critical value  of  \frac{\alpha }{2} at a degree of freedom of df =  24   is  

   t_{\frac{\alpha }{2} , 24 } = 3.0

Generally the margin of error is mathematically represented as  

      E = t_{\frac{\alpha }{2} , 24} *  \frac{\sigma }{\sqrt{n} }

=>     E = 3.0 *  \frac{3 }{\sqrt{25} }

=>     E =1.8

Gnerally the  upper control chart limit  for 99.7% confidence is mathematically represented as

         UCL  =  \= x  + E

=>      UCL  =  9 + 1.8  

=>      UCL  =  10.8  

     

4 0
3 years ago
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