This is the same as showing the following system of equations doesn't have a solution:

or in matrix form,

The quickest way to check if there is a solution is to check whether the coefficient matrix is invertible. If its determinant is 0, then it is not invertible.
And the quickest way to show that the determinant is 0 is by observing that the third row is a linear combination of the first two rows:
(-2, 9, 6) - (-3, 2, 1) = (-2 + 3, 9 - 2, 6 - 1) = (1, 7, 5)
So there are indeed no such scalars <em>c₁</em>, <em>c₂</em>, and <em>c₃</em>.
I do not get what the Question that you are asking is.
Answer:
D. 10
Step-by-step explanation:
To find the slope of the equation, we first need to put the equation into slope-intercept form:
y=mx+b
So first, we need to get y by itself.
10x-y=2
Subtract 10x from both sides.
-y=-10x+2
Then, divide -1 on both sides.
y=10x-2
Slope=10
4 x (n + 20), pretty simple. :)
Answer:
a.b=[-1]
Step-by-step explanation:
This is a dot product of a and b
a.b =[6,-2,3].[2,5, -1] = [12-10-3] =[-1]