f(x) > 0 - I and II quadrant
f(x) < 0 - III and IV quadrant
Look at the picture.
A. F(x) < 0 on the interval x < 0. TRUE
B. F (x) > 0 on the interval x <0. FALSE
C. F (x) < 0 on the interval 0 < x < 1. TRUE
D. F (x) > 0 on the interval 0 < x < 1. FALSE
E. F (x) < 0 on the interval 1 < x < 3. FALSE
F. F (x) > 0 on the interval 1 < x < 3. TRUE
G. F (x) < 0 on the interval x > 3. TRUE
H. F (x) > 0 on the interval x > 3. FALSE
To solve the problem shown bove you must apply the proccedure shown below:
1. You have that:
2a-1<<span>7−1.2a
2a+1.2a<7+1
3.2a<8
a<8/3.2
a<2.5
2. Therefore, f</span><span>or what values of a is the value of the binomial 2a−1 smaller than the value of the binomial 7−1.2a?
</span><span>
As you can see above, the answer for this question is:
All the values of a between -</span>∞ and 2.5<span>
</span>
Answer:
Cities A and C should be in Group 2
Step-by-step explanation:
Cities:
These should be in Group 2 because they are less than -3
Hope this helps!
Um this question is unclear
