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2 years ago

Which expression is equivalent to 4c+ c- 2c?

Mathematics

2 answers:

Mrrafil [7]2 years ago

6 0

Answer:

c+2

Step-by-step explanation:

Because you subtract 4c-2c=2 then the c left so c+2 is the anser.

harkovskaia [24]2 years ago

3 0

Answer: 3c

Step-by-step explanation: add 4 to 1 and take away 2.

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Explain why the expression 9x^3+1/2x^2+3x^-1 is not a polynomial

Nastasia [14]

Answer:

The given expression can't be expressed in polynomial form. Hence, it is not a polynomial.

Step-by-step explanation:

P(x,n) is a polynomial of nth degree if it is of the form,

P(x,n) = $a_{0} + a_{1}x + a_{2}x^{2} + a_{3}x^{3} + ......... +a_{n}x^{n}$

where n is a finite positive integer and n ∈ N

and ' $a_{i}$ 's are fixed but otherwise arbitrary constants ∀ i = 0(1)n .

Now, the given expression is,

$9x^{3} + \frac {1}{2x^{2}} + 3x^{-1}$

which doesn't fit in the above form. Hence, it is not a polynomial.

4 0

3 years ago

Suppose you have 12 coins that total 32 cents . Some of the coins are nickels and the rest are pennies . How many of each coin d

mario62 [17]

You will need 6 coins of 5
and 2 coins of 1
hope it helps

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8 0

3 years ago

A triangle is formed from the points L(-3, 6), N(3, 2) and P(1, -8). Find the equation of the following lines:

Dima020 [189]

Answer:

Part A) $y=\frac{3}{4}x-\frac{1}{4}$

Part B) $y=\frac{2}{7}x-\frac{5}{7}$

Part C) $y=\frac{2}{7}x+\frac{8}{7}$

see the attached figure to better understand the problem

Step-by-step explanation:

we have

points L(-3, 6), N(3, 2) and P(1, -8)

Part A) Find the equation of the median from N

we Know that

The median passes through point N to midpoint segment LP

step 1

Find the midpoint segment LP

The formula to calculate the midpoint between two points is equal to

$M(\frac{x1+x2}{2},\frac{y1+y2}{2})$

we have

L(-3, 6) and P(1, -8)

substitute the values

$M(\frac{-3+1}{2},\frac{6-8}{2})$

$M(-1,-1)$

step 2

Find the slope of the segment NM

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

N(3, 2) and M(-1,-1)

substitute the values

$m=\frac{-1-2}{-1-3}$

$m=\frac{-3}{-4}$

$m=\frac{3}{4}$

step 3

Find the equation of the line in point slope form

$y-y1=m(x-x1)$

we have

$m=\frac{3}{4}$

$point\ N(3, 2)$

substitute

$y-2=\frac{3}{4}(x-3)$

step 4

Convert to slope intercept form

Isolate the variable y

$y-2=\frac{3}{4}x-\frac{9}{4}$

$y=\frac{3}{4}x-\frac{9}{4}+2$

$y=\frac{3}{4}x-\frac{1}{4}$

Part B) Find the equation of the right bisector of LP

we Know that

The right bisector is perpendicular to LP and passes through midpoint segment LP

step 1

Find the midpoint segment LP

The formula to calculate the midpoint between two points is equal to

$M(\frac{x1+x2}{2},\frac{y1+y2}{2})$

we have

L(-3, 6) and P(1, -8)

substitute the values

$M(\frac{-3+1}{2},\frac{6-8}{2})$

$M(-1,-1)$

step 2

Find the slope of the segment LP

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

L(-3, 6) and P(1, -8)

substitute the values

$m=\frac{-8-6}{1+3}$

$m=\frac{-14}{4}$

$m=-\frac{14}{4}$

$m=-\frac{7}{2}$

step 3

Find the slope of the perpendicular line to segment LP

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

$m_1*m_2=-1$

we have

$m_1=-\frac{7}{2}$

$m_2=\frac{2}{7}$

step 4

Find the equation of the line in point slope form

$y-y1=m(x-x1)$

we have

$m=\frac{2}{7}$

$point\ M(-1,-1)$ ----> midpoint LP

substitute

$y+1=\frac{2}{7}(x+1)$

step 5

Convert to slope intercept form

Isolate the variable y

$y+1=\frac{2}{7}x+\frac{2}{7}$

$y=\frac{2}{7}x+\frac{2}{7}-1$

$y=\frac{2}{7}x-\frac{5}{7}$

Part C) Find the equation of the altitude from N

we Know that

The altitude is perpendicular to LP and passes through point N

step 1

Find the slope of the segment LP

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

we have

L(-3, 6) and P(1, -8)

substitute the values

$m=\frac{-8-6}{1+3}$

$m=\frac{-14}{4}$

$m=-\frac{14}{4}$

$m=-\frac{7}{2}$

step 2

Find the slope of the perpendicular line to segment LP

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

$m_1*m_2=-1$

we have

$m_1=-\frac{7}{2}$

$m_2=\frac{2}{7}$

step 3

Find the equation of the line in point slope form

$y-y1=m(x-x1)$

we have

$m=\frac{2}{7}$

$point\ N(3,2)$

substitute

$y-2=\frac{2}{7}(x-3)$

step 4

Convert to slope intercept form

Isolate the variable y

$y-2=\frac{2}{7}x-\frac{6}{7}$

$y=\frac{2}{7}x-\frac{6}{7}+2$

$y=\frac{2}{7}x+\frac{8}{7}$

7 0

3 years ago

*The rectangle to the left is divided into 12 shapes. One of them is a rectangle labeled with #1 and the remaining 11 shapes are

Mandarinka [93]

Given that the length of side of shaded area is 1 ft.

Making equal square of size of shaded area we have:

Horizontally number of shaded area are 12

Vertically number of shaded area are 11

So, the horizontal length of big rectangle is 12 ft.

The vertical length of big rectangle is 11 ft.

Area of big rectangle is 12*11

Area of given rectangle is 132 sq.ft.

6 0

3 years ago

I need help plsssss✨

Blababa [14]

Answer:

With?

Step-by-step explanation:

4 0

2 years ago

Which expression is equivalent to 4c+ c- 2c?​

Which expression is equivalent to 4c+ c- 2c?