We know, equation of ellipse is given by :
Here,
(h,k) is centre of the ellipse = (0,0).
a = major axis = 8.
b = minor axis = 4.
Putting all given value in above equation, we get :
Hence, this is the required solution.
I: 12x-5y=0
II:(x+12)^2+(y-5)^2=169
with I:
12x=5y
x=(5/12)y
-> substitute x in II:
((5/12)y+12)^2+(y-5)^2=169
(25/144)y^2+10y+144+y^2-10y+25=169
(25/144)y^2+y^2+10y-10y+144+25=169
(25/144)y^2+y^2+144+25=169
(25/144)y^2+y^2+169=169
(25/144)y^2+y^2=0
y^2=0
y=0
insert into I:
12x=0
x=0
-> only intersection is at (0,0) = option B
Yes. 450 ÷ 9 = 50, 450 ÷ 5 = 90, 450 ÷ 10 = 45
Answer:
2 points the first 3 matches then 3 points the last 2 matches
Step-by-step explanation:
12 points in 5 matches and the first 3 are all the same then the other 2 increased by 1 point
They got 2 points the first 3 matches then 3 points the last 2 matches
2 + 2 + 2 (first 3 matches) = 6
3 + 3 (last 2 matches) = 6
6 + 6 = 12
Answer:
x=4
Step-by-step explanation:
3x = 12
divide by 3
x =12/3
