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Leona [35]
2 years ago
10

A box with a height (x+5) has a square base with side x. A second box with height (x+2) has a square base with side (x+5). If th

e two boxes have the same volume, find the value of x
Mathematics
1 answer:
sergeinik [125]2 years ago
4 0

Answer :

x = -1.43

Explanation :

As given ,

The first box has a height (x+5) has a square base with side x

So, the Length and Breadth of the box are x and x respectively.

Now,

The volume of first box = Length×Breadth×Height

                                       = (x).(x).(x+5)

                                       = x²(x+5)

⇒The volume of first box = x²(x+5)

Now,

Given that , the second box with height (x+2) has a square base with side (x+5).

So, the Length and Breadth of the box are (x+5) and (x+5) respectively.

Now,

The volume of second box = Length×Breadth×Height

                                             =  (x+5). (x+5).(x+2)

                                              = (x+5)²(x+2)

⇒The volume of second box =  (x+5)²(x+2)

Now,

Given that,  the two boxes have the same volume

⇒x²(x+5) =  (x+5)²(x+2)

⇒x² =  (x+5)(x+2)

⇒x² =  x² + 2x + 5x + 10

⇒x² - x² =  7x + 10

⇒0 =  7x + 10

⇒ 7x = -10

⇒ x = -\frac{10}{7} = -1.43

⇒ x = -1.43

As volume of first box = x²(x+5) = (-1.43)²(-1.43+5) = 7.30 ≈ 7

As volume of second box =  (x+5)²(x+2) = (-1.43+5)²(-1.43+2) = 7.26 ≈ 7

At x = -1.43, Volume of both the boxes are same.

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Answer:

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Wally wants to determine the height of a statue that casts a 164-inch shadow by comparing it to his own height and shadow length
nataly862011 [7]

We have been given that Wally wants to determine the height of a statue that casts a 164-inch shadow by comparing it to his own height and shadow length. Wally is 68 inches tall, casts a shadow that is 41 inches in length.

We will use proportions to solve for the height of the statue because proportions state that ratio between two proportional quantities is same.

\frac{\text{Height of statue}}{\text{Shadow of statue}}=\frac{\text{Height of Wally}}{\text{Shadow of Wally}}

Upon substituting our given values in above equation, we will get:

\frac{\text{Height of statue}}{\text{164 cm}}=\frac{\text{68 inch}}{\text{41 inch}}

\frac{\text{Height of statue}}{\text{164 cm}}\times \text{164 cm}=\frac{\text{68 inch}}{\text{41 inch}}\times \text{164 cm}

\text{Height of statue}=\frac{\text{68 inch}}{1}\times 4

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Therefore, the height of the statue is 272 inches.

5 0
2 years ago
3.
sergey [27]

Answer:

His money earned $36 after 3 months

Step-by-step explanation:

* Lets revise the rules of simple interest

- Simple Interest Equation (Principal + Interest)

 A = P(1 + rt)

- Where:

• A = Total amount (principal + interest)  future amount

• P = Principal Amount

• I = Interest Amount

• r = Rate of Interest per year in decimal; r = R/100

• t = Time Period involved  

* To calculate the interest I use the formula

  I = P × r × t

* Lets solve the problem

- The rate is annual

- The interest calculated after 3 months

∴ I = P × R/100 × t/12

∵ P = $3600.00

∵ R = 4%

∵ t = 3 month

∴ I = 3600.00 × 4/100 × 3/12 = $36

* His money earned $36 after 3 months

5 0
3 years ago
How do you do this please help
nadezda [96]
You can create the equation 1.20x + 2.50y = 300
Where 1.20 is the price of each vinca flower, x is how many vinca you will buy, 2.50 is the price of each phlox flower, y is how many plhox you will buy and 300 is how much money you have.

To get three combinations of how many plhox and vinca flowers you ( or the gardner can buy) with 300, you can just take a random value for x or y, apply it to the equation and then solve the equation for the other
variable ( x or y).
This means:
Pick a number of how many flower you will get of ONE type of flower ( ONLY ONE)
The gardner will not get any Vinca flowers, then x = 0
( as x = how many vinca flower the gardner will get)
now apply 0 to x ( this means substitute x with 0)

(1.20)(0) + 2.50y = 300
Since any number x 0 is 0, the equation will be
0 + 2.50y = 300 or just 2.50y = 300

Now to solve an equation we just need to isolate the variable (y) on one side of the equation and the value on the other.
We can do that by dividing both sides of the equation, so 2.50y turns into 2.50/2.50 times y which is just y.

2.50/2.50 y = 300/2.50
y = 120
And since we chose the value for how many vincas we would buy, we have the x value as well ( 0)
x = 0

So 1 combination can be: 0 Vinca and 120 Plhox

Combination #2 ( I ll stop explaining the steps since I already explained how to do it)

y = 0 ( I chose not to buy any Plhox)

1.20x + (2.50)(0) = 300
1.20x = 300
1.20/120x = 300/120x
x = 25
y= 0
Combination 2: 25 Vincas and 0 plhox

Combination #3:
x = 100 ( I chose to buy 10 vincas)
(1.20)(100) + 2.50y = 300
120 + 2.50y = 300
( I didnt explain thow to isolate a variable in this situation so ill explain it: to isolate this esquation we can subtract 12 from both sides of the equation so 12 cancels out. We need to do it on both sides because otherwise the first side wouldnt be equal to the other sode, and that wouldnt be an equation)

120 - 120 + 2.50y = 300 - 120
2.50y = 180
y = 72
x = 100

Combination 3: 100 Vinca and 72 Plox

I know this is long but I hope it was helpful to you if you didnt know how to solve equations :)


3 0
3 years ago
Ann is adding water to a swimming pool at a constant rate. The table below shows the amount of water in the pool after different
N76 [4]

Answer:

(a)  As time increases, the amount of water in the pool increases.

     11 gallons per minute

(b)  65 gallons

Step-by-step explanation:

From inspection of the table, we can see that <u>as time increases, the amount of water in the pool increases</u>.

We are told that Ann adds water at a constant rate.  Therefore, this can be modeled as a linear function.  

The rate at which the water is increasing is the <em>rate of change</em> (which is also the <em>slope </em>of a linear function).

Choose 2 ordered pairs from the table:

\textsf{let}\:(x_1,y_1)=(8, 153)

\textsf{let}\:(x_2,y_2)=(12,197)

Input these into the slope formula:

\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{197-153}{12-8}=\dfrac{44}{4}=11

Therefore, the rate at which the water in the pool is increasing is:

<u>11 gallons per minute</u>

To find the amount of water that was already in the pool when Ann started adding water, we need to create a linear equation using the found slope and one of the ordered pairs with the point-slope formula:

y-y_1=m(x-x_1)

\implies y-153=11(x-8)

\implies y-153=11x-88

\implies y=11x-88+153

\implies y=11x+65

When Ann had added no water, x = 0.  Therefore,

y=11(0)+65

y=65

So there was <u>65 gallons</u> of water in the pool before Ann starting adding water.

3 0
2 years ago
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