2 years ago

PLEASE HELP ITSS TIMED!!!

1 answer:

NARA [144]2 years ago

3 0

It would be distributive because you distribute what is in the parentheses

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aev [14]

Answer:

D. No, because $P(A|B)=0.22$ and the $P(A) = 0.53$ are not equal.

Step-by-step explanation:

Given:

Probability of doing yard work is, $P(A)=53\%=0.53$

Probability of raining, $P(B)=68\%=0.68$

Probability of doing yard work and it raining is, $P(A\cap B)=15\%=0.15$

Now, two events A and B are independent if,

$P(A|B)=P(A);P(B|A)=P(B)$

Conditional probability of event A given that B has occurred is given as:

$P(A|B)=\frac{P(A\cap B}{P(B)}\\P(A|B)=\frac{0.15}{0.68}=0.22$

So, $P(A|B)=0.22\ and\ P(A)=0.53$

Since, $P(A|B)\ne P(A)$ , A and B are not independent events.

8 0

3 years ago

liberstina [14]

2=6-3 is the direct variation

4 0

2 years ago

7nadin3 [17]

the answer is 28 hoped that helped

5 0

3 years ago

Veronika [31]

Answer: x=90

Step-by-step explanation: 11 x 7.5 =90

8 0

3 years ago

artcher [175]

Hope this helps but I think it is A.)addition property of equality.

6 0

3 years ago