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maxonik [38]
3 years ago
13

A freight train initially moving at +10m/s decelerates at a rate of -0.1m/s^2. How far does it move in 30 seconds?

Physics
2 answers:
Kaylis [27]3 years ago
8 0

Answer:

255 [m].

Explanation:

1) the formula is (d - requred distance, V₀ - initial velocity, t - elapsed time, a - deceleration):

d=V_0t+\frac{at^2}{2};

2) according to the formula above the required distance is:

d=10*30-0.5*0.1*900=300-45=255 [m].

siniylev [52]3 years ago
7 0
  • Initial velocity=u=10m/s
  • Acceleration=-0.1m/s^2=a
  • Time=t=30s

  • Distance=s

Apply second equation of kinematics

\\ \tt\longmapsto s=ut+\dfrac{1}{2}at^2

\\ \tt\longmapsto s=10(30)+\dfrac{1}{2}(-0.1)(30)^2

\\ \tt\longmapsto s=300+(-0.1)(450)

\\ \tt\longmapsto s=300-45

\\ \tt\longmapsto s=255m

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