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Scorpion4ik [409]
3 years ago
7

Kyle's science class is doing an experiment to find out about the effects of different temperatures on Mexican jumping beans. Th

e teacher has divided the class into different groups. Each group will conduct their experiment and report back to the class on their findings.
During the experiment, Kyle's group made an error with a temperature measurement. The error was corrected. Should the mistake be shared with the class? Why or why not?
Physics
1 answer:
gizmo_the_mogwai [7]3 years ago
7 0

Answer:

Yes, to educate other groups on possible measurement errors that can cause variation in results

Explanation:

Having divided the class in groups, the teacher expects the results of all groups if doing similar experiment to be within a certain range. In case Kyle's group never corrected the error, they could have results out of range as expected. It is prudent that the mistake be shared with the whole class so that in future there should not be a repeat of the same.

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3 years ago
Ten identical steel wires have equal lengths L and equal "spring constants" k. The wires are connected end to end so that the re
lapo4ka [179]

Answer:

K_{system} = \frac{k}{10}

Explanation:

When the springs are connected end to end, it means they are connected in series. When the springs are connected in series, the stress applied to the system gets applied to each of the springs without any change in magnitude while the strain of the system is the sum total of strains of each spring. The spring constant of the resultant system is given as,

\frac{1}{K_{system}} = (\frac{1}{K_{1}})+(\frac{1}{K_{2}})+(\frac{1}{K_{3}})+ (\frac{1}{K_{4}})+.....+(\frac{1}{K_{n}})

Here, n = 10

Spring constant of each spring = k

Thus,

\frac{1}{K_{system}} = (\frac{1}{K_{1}})+(\frac{1}{K_{2}})+(\frac{1}{K_{3}})+ (\frac{1}{K_{4}})+.....+(\frac{1}{K_{10}})

\frac{1}{K_{system}} = (\frac{1}{k})+(\frac{1}{k})+(\frac{1}{k})+(\frac{1}{k})+(\frac{1}{k})+(\frac{1}{k})+(\frac{1}{k})+(\frac{1}{k})+(\frac{1}{k})+(\frac{1}{k})

\frac{1}{K_{system}} = \frac{10}{k}

K_{system} = \frac{k}{10}

7 0
3 years ago
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